Nothing, as the speed of sound doesn't change (about 340 metres per second in air). If the frequency (or pitch) were to be twice as high it would simply halve the wavelength.
IF a wave moving at a constant speed were to have it's wavelength doubled (Wavelength x 2), then the frequency of the wave would be half of what it originally was (Frequency / 2).
Wavelength is halved.
The wave length would necessarily be one half. The speed would remain the same independent of the frequency.
Wavelength = 1/frequency. If you double the frequency, the wavelength drops to half.
The frequency also doubles of the wave length stays the same. Remember that Velocity = (the wavelength) x (the frequency)
IF a wave moving at a constant speed were to have it's wavelength doubled (Wavelength x 2), then the frequency of the wave would be half of what it originally was (Frequency / 2).
The speed halves.
The speed halves.
The speed halves.
speed = freq. X wavelength Hence frequency and wavelength are inversely related when the speed is same. So if the frequency is doubled, then wavelength becomes half of the initial length.
Nothing happens
Wavelength is halved.
The wave length would necessarily be one half. The speed would remain the same independent of the frequency.
Wavelength = 1/frequency. If you double the frequency, the wavelength drops to half.
The frequency also doubles of the wave length stays the same. Remember that Velocity = (the wavelength) x (the frequency)
Nothing happens
Assuming that the wavelength remains constant, the velocity of the rope will also double if the frequency is doubled. This can be seen in the word equation below: speed = frequency x wavelength If we assume that wavelength is a constant...let wavelength = 1 speed = frequency therefore... 2 x frequency = 2 x speed