Q: If there are three consecutive numbers and the sum is 36 what are the three numbers?

Write your answer...

Submit

Related questions

The numbers are 11, 12 and 13.

The numbers are 11, 12 and 13.

The numbers are 36, 37 and 38.

Assuming you mean how to solve what three consecutive numbers sum to some value: Divide the sum by three to get the middle number. The other two numbers are one less than this and one more than it. example: Which three consecutive numbers sum to 108? 108 ÷ 3 = 36 → The other two numbers are 36 - 1 = 35 and 36 + 1 = 37 → The three numbers are 35, 36, 37. 35 + 36 + 37 = 108 as required.

The numbers are 32, 34, and 36.

36, 37, 38 36+37+38=111

36 + 37 + 38 = 111

102 = 32 + 34 + 36

10, 12, 14 are the consecutive even #'s that equal 36

1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36

(-11) + (-12) + -(13) = -36

All the odd numbers.

11,12,13

You may mean: 32+34+36 = 102

-13, -12, & -11.

36 / 3 = 13. So lets try 10, 12, 1410 +12+14 = 36

The integers are -14, -12 and -10.

Call the smallest number x, which makes the next two consecutive even numbers x+2 and x+4. The sum of these three numbers is 36, so: x + (x + 2) + (x + 4) = 36 3x + 6 = 36 3x = 36 - 6 = 30 x = 10 So the three numbers are 10, 12, and 14, which indeed total 36. So the largest number is 14. Note that the question was about consecutive even numbers. Had the question just been about consecutive numbers, the numbers would be x, x+1, and x+2, so you'd get x + (x+1) + (x+2) = 36, 3x + 3 = 36, 3x = 33, x=11. The three numbers would be 11, 12, and 13, so the answer would be 13.

No, they are consecutive but sum means that if you add them together it will equal 36. Also 2 is not odd. The numbers you are looking for are 17 and 19.

10 12 14 are the consecutive even integers which add up to 36

36+37=73

The numbers are 36, 37 and 38.

10 12 14

35+36+37

25+36=61 is that what you want to hear?