11, 12, and 13
The numbers are 11, 12 and 13.
The numbers are 36, 37 and 38.
The numbers are 32, 34, and 36.
102 = 32 + 34 + 36
11, 12, and 13
The numbers are 11, 12 and 13.
The numbers are 36, 37 and 38.
Assuming you mean how to solve what three consecutive numbers sum to some value: Divide the sum by three to get the middle number. The other two numbers are one less than this and one more than it. example: Which three consecutive numbers sum to 108? 108 ÷ 3 = 36 → The other two numbers are 36 - 1 = 35 and 36 + 1 = 37 → The three numbers are 35, 36, 37. 35 + 36 + 37 = 108 as required.
The numbers are 32, 34, and 36.
36, 37, 38 36+37+38=111
36 + 37 + 38 = 111
102 = 32 + 34 + 36
10, 12, 14 are the consecutive even #'s that equal 36
1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36
You may mean: 32+34+36 = 102
36 / 3 = 13. So lets try 10, 12, 1410 +12+14 = 36