Q: Three consecutive numbers have a sum of 36?

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11, 12, and 13

The numbers are 11, 12 and 13.

The numbers are 36, 37 and 38.

The numbers are 32, 34, and 36.

102 = 32 + 34 + 36

Related questions

11, 12, and 13

The numbers are 11, 12 and 13.

The numbers are 36, 37 and 38.

Assuming you mean how to solve what three consecutive numbers sum to some value: Divide the sum by three to get the middle number. The other two numbers are one less than this and one more than it. example: Which three consecutive numbers sum to 108? 108 ÷ 3 = 36 → The other two numbers are 36 - 1 = 35 and 36 + 1 = 37 → The three numbers are 35, 36, 37. 35 + 36 + 37 = 108 as required.

The numbers are 32, 34, and 36.

36, 37, 38 36+37+38=111

36 + 37 + 38 = 111

102 = 32 + 34 + 36

10, 12, 14 are the consecutive even #'s that equal 36

1, 3, 5, 7, 9, 11 are six consecutive odd numbers whose sum is 36

You may mean: 32+34+36 = 102

36 / 3 = 13. So lets try 10, 12, 1410 +12+14 = 36