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If you don't put the first one back in the bag before the second draw, then the total
possible number of draws is (10 x 9) = 90, and only one of them is successful. So the
probability is 1/90 = 0.0111 = 1.11% (rounded).

If you do put the first one back in the bag before the second draw, then the total possible
number of draws is (10 x 10) = 100, and only one of them is the one you want. So the
probability is 1/100 = 0.01 = 1%.

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Q: If there is a bag that contains marbles numbered 1-10 what is the probability that you would get a 9 then a 3?
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