15/21= 71.43% chance. It's the number of possible throws without repetition divided by the total different combinations of dice throw. Here is a handy Combination and Permutation Calculator: http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html
There are 6 possible numbers that can be rolled. "4" is one of those possible numbers. Probability is therefore 1/6.
The probability is 1, if the dice are rolled often enough.
If you're only rolling one die, it's a probability of 1 out of six, or 16.67%.
It is 1/6.
It is 0.9459
There are 6 possible numbers that can be rolled. "4" is one of those possible numbers. Probability is therefore 1/6.
The probability is 1, if the dice are rolled often enough.
If you're only rolling one die, it's a probability of 1 out of six, or 16.67%.
I'm assuming you multiply the numbers rolled. Thus the rules of even and odd numbers come into play. The only way to get an odd product is to roll two odd numbers. The probability desired is 1 minus the probability of rolling two odd numbers. The odds of rolling an odd number is 1/2. Since the rolls are independent events, the odds of rolling two odd numbers is (1/2)2 = 1/4 So the probability of getting an even product is: 1 - 1/4 = 3/4
It is 1/6.
Assuming that the random variable is the sum of the two numbers rolled, the answer is 3/36 or 1/12.
1/6
It is 0.9459
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
Because 3/6 of the sides on a number cube have even numbers, the probability of rolling even on one number cube is 1/2(equivalent of 3/6). But since you're rolling twice, you multiply the probability of one by itself (therefore rolling 2 number cubes). So: 1/2x1/2=1/4 The probability of rolling an even number when a number cube is rolled twice is 1/4, 25%, or 1 out of 4.
The probability is 1, if the dice are rolled often enough.
If you rolled 2 fair dice, the probability of having a sum of 6 is 5 over 36