x2 + y2 = 49
The circle's radius is 7. That's all we need to know about it for this question.
Diameter = 2 x radius = 14.
Circumference = (pi) x (diameter) = 14 pi
Central angle of 30° = (30/360) = 1/12 of the whole circle
Length of the minor arc 'ab' = (14 pi)/12 = (7 pi) / 6
It is certainly possible. All you need is a the second circle to have a radius which is less than 20% of the radius of the first.
The relation between the arc of length and the central angle is that the arc of length divided by one of the sides is the central angle in radians. If the arc is a full circle, then the central angle is 2pi radians or 360 degrees.
arc length/circumference = central angle/2*pi (radians) So, central angle = 2*pi*arc length/circumference = 4.54 radians. Or, since 2*pi radians = 360 degrees, central angle = 360*arc length/circumference = 260.0 degrees, approx.
Well, in degrees, the arc is congruent to its central angle. If the radius is given, however, just find the circumference of the circle (C=πd). Then, take the measure of the central angle, and divide that by 360 degrees. Multiply the circumference by the dividend, and you will get the arc length. This works because it is a proportion. Circumference:Arc length::Total degrees in triangle:Arc's central angle. Hope that helped. :D
It depends on the length of the arc because there are a total of 360 degrees in a complete circle.
The radial length equals the chord length at a central angle of 60 degrees.
The length of an arc on a circle of radius 16, with an arc angle of 60 degrees is about 16.8.The circumference of the circle is 2 pi r, or about 100.5. 60 degrees of a circle is one sixth of the circle, so the arc is one sixth of 100.5, or 16.8.
The measure of the central angle divided by 360 degrees equals the arc length divided by circumference. So 36 degrees divided by 360 degrees equals 2pi cm/ 2pi*radius. 1/10=1/radius. Radius=10 cm.
The measure of the central angle divided by 360 degrees equals the arc length divided by the circumference. So 18 degrees/360 degrees=arc length/(9 feet*2pi). 1/20=arc length/18pi feet; arc length=9pi/10 feet. It's refreshing to answer a question that is written with grammatical accuracy!
5.23
2pi/9 radians or 40 degrees
-- Circumference of the circle = (pi) x (radius) -- length of the intercepted arc/circumference = degree measure of the central angle/360 degrees
It is certainly possible. All you need is a the second circle to have a radius which is less than 20% of the radius of the first.
The relation between the arc of length and the central angle is that the arc of length divided by one of the sides is the central angle in radians. If the arc is a full circle, then the central angle is 2pi radians or 360 degrees.
A central angle is measured by its intercepted arc. Let's denote the length of the intercepted arc with s, and the length of the radius r. So, s = 6 cm and r = 30 cm. When a central angle intercepts an arc whose length measure equals the length measure of the radius of the circle, this central angle has a measure 1 radian. To find the angle in our problem we use the following relationship: measure of an angle in radians = (length of the intercepted arc)/(length of the radius) measure of our angle = s/r = 6/30 = 1/5 radians. Now, we need to convert this measure angle in radians to degrees. Since pi radians = 180 degrees, then 1 radians = 180/pi degrees, so: 1/5 radians = (1/5)(180/pi) degrees = 36/pi degrees, or approximate to 11.5 degrees.
arc length/circumference = central angle/2*pi (radians) So, central angle = 2*pi*arc length/circumference = 4.54 radians. Or, since 2*pi radians = 360 degrees, central angle = 360*arc length/circumference = 260.0 degrees, approx.
The length of an arc of a circle refers to the product of the central angle and the radius of the circle.