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The general idea is to solve one of the equations for one variable - in terms of the other variable or variables. Then you can substitute the entire expression into another equation or other equations; as a result, if it works you should end up having one less equation, with one less variable.
The evaluate a algebraic math expression you first must substitute a number for each variable. Then you must perform the operation in the correct order.
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
Not necessarily.A variable can hold other types of values, not just numbers. For example, a variable can hold a date, a text (also know as "string"), a boolean (true or false) value, etc. In object-oriented programming, you basically make up your own data types.An array variable can hold several related values. The individual values are usually distinguished by a number, called a subscript. (In other words, you have the first element, the second element, etc. in the array.)
first, you have to divide. Then, you have to add X to what you got when you divided. After that, you shove it up your butt and cry
in the first column on the left
yes
No. To evaluate a variable, you simply take its value. When you assign a value to a variable, the evaluation of that operation is the value of the variable after assignment. There is no calculation required to evaluate a variable, unless that calculation is part of the right-hand operand of an assignment operation, in which case the calculation is evaluated first and the result of that evaluation (the value) is then assigned to the variable which is then evaluated.
The general idea is to solve one of the equations for one variable - in terms of the other variable or variables. Then you can substitute the entire expression into another equation or other equations; as a result, if it works you should end up having one less equation, with one less variable.
The evaluate a algebraic math expression you first must substitute a number for each variable. Then you must perform the operation in the correct order.
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
Write an expression consisting of up to three terms:One term in which the key variable is squared,one term with a multiple of the variable, anda constant.The first of these MUST be present. The three terms must be added or subtracted.
the first number in an ordered pair is the x coordinate it is one of the values that the independent variable has taken on
By shifting the values in an array, you are moving a key's value to the previous key. The very first key's value is obliterated. By shifting all values in the array, all keys will have a value of NULL. Unsetting a variable is entirely different -- performing a variable unsetting causes the variable to have a value of NULL, as if it was never set.
the first number in an ordered pair is the x coordinate it is one of the values that the independent variable has taken on
In the first expression the value is 91 times as large as it is in the second.
Consider this expression: x2-5x+6 And you know that it is a perfect square trinomial. Therefore, you also know that there will be two parenthetical expressions that, when multiplied, will yield x2-5x+6. Keep this in mind throughout the process. Start with the "skeleton". Draw your parentheses. ( )( ) Take the square root of the first number in the expression. In this case, x2. (x )(x ) So now you're all set with the first value in the expression. Once you're sure that the square root is correct, you don't need to go back. ***(This is only true as long as there is no numerical value in front of the variable) Next, think of numbers that, when added, will equal the middle value and that, when multiplied, will equal the third value. In this case, numbers that equal -5 when added, and 6 when multiplied. (You don't need to worry about the variable for the middle value. It does make its way into the unsimplified expression). -2 and -3 are the values So insert the values in the expression. (x-2)(x-3) Multiply the expression out to check the simplification And done!