Use the equation, 1/f = 1/di + 1/do
So, di/f = 1+1/m (m = magnitude)
If we are trying to find twice the distance, m=2
Therefore, di/f = 1+1/2
di/f = 1.5
Take the focal length out and plug it into the problem and you have, di = 8.5*1.5
So finally, di = 12.75
The piece of paper would have to be placed at 12.75cm in order for the real image to appear twice as far as the object.
1/object distance + 1/ image distance = 1/focal length
A concave mirror bulges away from the incident light. The image of an object depends on where exactly the object is placed - relative the to focal length of the mirror. See the attached link for more details.
40cm
1/o + 1/i = 1/ff = (o x i)/(o + i)f = 11.1 cm (rounded)
A concave lens will appear!
If an object's distance from the concave mirror is greater than the mirror's focal length, then the mirror image of it will be inverted. If the distance from the concave mirror is less than the focal length of the mirror, the image will not be inverted. No image will be produced if the distance from the mirror to the object is equal to the mirror's focal length.
c. 8 millimeters
1/object distance + 1/ image distance = 1/focal length
A concave mirror bulges away from the incident light. The image of an object depends on where exactly the object is placed - relative the to focal length of the mirror. See the attached link for more details.
40cm
This is for a concave spherical mirror. This depends on if the image is insed or outside the foacl point of the lens. If the image is outside the foacl point of the lense it is then inverted (upside down), smaller in magnification, and is a real image which means the rays converge to create a real image that can be projected. If the object is inside the foacl point of the lens then the image has a negative image distance (through the mirror), is upright, is larger (magnification), and is a virtual image constructed from diverging light rays and cannot be projected.
The object should be necessarily be placed between the focal point of the concave mirror and the pole of the mirror to produce a larger image(not larger object) behind the concave mirror.
real and inverted
Sum of reciprocal of object distance and reciprocal of image distance gives the reciprocal of focal length
Sum of reciprocal of object distance and reciprocal of image distance gives the reciprocal of focal length
The spoon acts as a concave mirror at it's "loading surface". The idol of an object through a concave mirror which is further than the doubled focal length of it, is real, smaller and inverted (upside-down).
Virtual or real image... concave mirrors can form either virtual images or real images... i hope the answer would help you :)) Place the object closer to the mirror than its focal length.