1/o + 1/i = 1/f
f = (o x i)/(o + i)
f = 11.1 cm (rounded)
1/object distance + 1/ image distance = 1/focal length
A concave mirror bulges away from the incident light. The image of an object depends on where exactly the object is placed - relative the to focal length of the mirror. See the attached link for more details.
40cm
The distance of the object from the mirror line should equal the distance of the image from the mirror line.
Use 1/s + 1/s' = 1/f s = 20cm f = +10cm (positive since the mirror is concave) 1/s'=1/f - 1/s 1/s'=1/10 - 1/20 = 1/20 So, s'=20cm. The distance from the image to the mirror is 20cm, which is not surprising, since the object placed at 1/2 of the focal length and therefore exactly at the radius of curvature point. The image is real and inverted.
If an object's distance from the concave mirror is greater than the mirror's focal length, then the mirror image of it will be inverted. If the distance from the concave mirror is less than the focal length of the mirror, the image will not be inverted. No image will be produced if the distance from the mirror to the object is equal to the mirror's focal length.
1/object distance + 1/ image distance = 1/focal length
Sum of reciprocal of object distance and reciprocal of image distance gives the reciprocal of focal length
Sum of reciprocal of object distance and reciprocal of image distance gives the reciprocal of focal length
Distance from the mirror, curvature of the mirror.
distance from mirror
distance from mirror
Distance from the mirror, curvature of the mirror.
A concave mirror bulges away from the incident light. The image of an object depends on where exactly the object is placed - relative the to focal length of the mirror. See the attached link for more details.
40cm
The object should be necessarily be placed between the focal point of the concave mirror and the pole of the mirror to produce a larger image(not larger object) behind the concave mirror.
real and inverted