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If you have a set of 40 numbers how do you calculate the number of all the possible combinations of 5 numbers from the set?
Wiki User
∙ 14y ago
By making a number tree that could have as many as 1,000,000 combos.
Wiki User
∙ 14y ago
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What are the possible combinations of a 3 digit lock for numbers 0 through 39?
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
How many combinations of 6 numbers are there if you have 10 numbers to choose from?
If the order of the numbers are important, then this is a simple combination problem. There are 10 possible numbers to choose from for the first number. Then there are 9 options for the second number. Then there are 8 options for the third, and so on. Thus, the number of possible combinations can be calculated as 10x9x8x7x6x5. This comes out at 151,200 possible combinations.
How many number combinations are possible with three numbers?
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
What are the 5-number combinations not using any number twice?
There are infinitely many numbers and so infinitely many possible combinations.
How many number combinations are possible with the same three numbers?
Six * * * * * No, that is the number of PERMUTATIONS (not combinations). With 3 numbers, the number of combinations, including the null combination, is 23 = 8. With the three numbers 1,2 and 3, these would be {None of them}, {1), {2), {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}.
What are the possible combinations of a 3 digit lock for numbers 0 through 39?
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
How many number combinations are possible with three numbers?
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
How many combinations of 6 numbers are there if you have 10 numbers to choose from?
If the order of the numbers are important, then this is a simple combination problem. There are 10 possible numbers to choose from for the first number. Then there are 9 options for the second number. Then there are 8 options for the third, and so on. Thus, the number of possible combinations can be calculated as 10x9x8x7x6x5. This comes out at 151,200 possible combinations.
What are the 5-number combinations not using any number twice?
There are infinitely many numbers and so infinitely many possible combinations.
How many 3 number combinations are possible with numbers 1234?
4 of them. In a combination the order of the numbers does not matter.
How many possible combinations of 3 letters can you make?
As there are 26 letters in the alphabet. You can calculate the number of combinations by multiplying 26x26x26, giving you the answer 17576.
How many 3 number combinations are possible with 1234?
Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.
How many six number combinations are possible with the numbers one to thirty five?
figure it out then tell me :)
Which numbers would A B and C be if AxBxC equals 1568?
There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.
How many combinations can you make with the numbers 2 3 6 7 and 8?
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
How many number combinations are possible with the same three numbers?
Six * * * * * No, that is the number of PERMUTATIONS (not combinations). With 3 numbers, the number of combinations, including the null combination, is 23 = 8. With the three numbers 1,2 and 3, these would be {None of them}, {1), {2), {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}.
If using numbers 1 thru 49 how many 6 digit combinations can be made?
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
