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Acceleration from gravity is 9.8 m/s2 or 32.2 ft/s2.

The Empire State Building is 381 meters/1,250 feet tall. So if we throw a penny off the Empire State Building, its speed would increase by 9.8m/32.2ft every second.

We will count every second's increasing speed.

9.8m for the first second.

32.2ft for the first second.

We keep adding 9.8m to the speed for every second that passes.

We keep adding 32.2ft to the speed for every second that passes.

On the eighth second, the penny will have passed 352.8m or 1157.5ft. The current speed for the ball is 78.4 m/s or 257.2 ft/s. We increase that by half of 9.8 m/s or half of 32.2 ft/s (4.9 m/s and 16.1 ft/s). The speed of the penny will now be 83.3 m/s or 273.3 ft/s. There is 28.2m or 92.5ft. This value divided by the current speed is 0.34. This will be the seconds left before impact on the ground.

8 + 0.34 = 8.34

It will take a penny 8.34 seconds to hit the ground when dropped from the Empire State Building. Terminal Velocity would slow it down much before it reached that point.

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Q: If you throw a penny off the empire states building how long will it take to hit the ground?
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