1 second, since all objects fall at 16 feet per second.
-- Take a heavy object and a stopwatch. -- Start the timer as you drop the object from the unknown height. -- Stop the timer when the object hits the ground. -- Read the time off the watch, in seconds. Square it. (Multiply it by itself.) -- Multiply that result by 16.1 . -- Now you have the distance the object fell, in feet.
Its acceleration is always the same - the acceleration of gravity at 32 ft/sec/sec - no matter what distance it is during drop, until it hits the ground.
iron bar first
The ball which you drop from 5 feet will reach the ground first.
if you ignore air resistance, it would take about 3.5 seconds; at ttat point where it hits the ground it is traveling at 75 mph. Because of the air drag, it may take a bit longer to hit the ground.
1second
It depends on what height you drop it from.
It is quite obvious, it will just hit the ground. The force depending on the height you dropped it from. For example: If you drop it from a high height it may shatter or it may land with more pressure. If you drop it from a low height it will simply drop with hardly any pressure.
There are many factors that can affect the time for these objects to drop. The height at which each object is dropped is a factor since the height is proportional to time. if the height at which these objects are dropped are the same, then the time for them to drop to the floor is the same. Since the acceleration due to gravity at sea level is 9.81 m/s^2 for all objects no matter the mass, both objects will accelerate at the same rate which means they will reach the floor at the same rate. All in all, both the pencil and the penny will hit the ground at the same time.
If a penny and a text book were dropped in a vacuum then they will both hit the ground at the same time. This refers to Newton's laws. If they are dropped at the same time on earth then the text book would hit the ground first.
Neglecting air resistance ...X = 1/2 G t2 = 1/2 (9.8) (4.82)2 = (4.9) (23.2324) = 113.84 meters (373.5 ft) (rounded)
Theoretically each will hit the ground at the exact same time. Practically, however, the distance from the drop position to the ground is a very impotant factor. If you drop both at a relatively short distance (say 5 feet) they will effectually hit at the same time if they encounter no wind resistance. If you drop them at a much higher distance (say 100 feet) the quarter will hit the ground before the penny. The reason being is resistance to the flat surface of the penny verses the quarter. Since the penny is much lighter than the quarter (a penny weighs 2.5 grams and a quarter weighs 5.67 grams) it will be affected to a greater degree by wind resistance that the much heavier quarter. You can liken it as to a feather being dropped. The feather will flip and twist and float as it slowly drifts down to the ground. The quarter being heavier will drop less reactivly and have a much straighter decent and therefore hit the ground sooner.
-- Take a heavy object and a stopwatch. -- Start the timer as you drop the object from the unknown height. -- Stop the timer when the object hits the ground. -- Read the time off the watch, in seconds. Square it. (Multiply it by itself.) -- Multiply that result by 16.1 . -- Now you have the distance the object fell, in feet.
because it wants to be low enough to give a blowy
Yes. Drop a rock from the top of the height, and carefully measure the time it takes to hit the ground.If ' T ' is the number of seconds it falls, then the height is4.9 T2 metersor16.1 T2 feet.
depends on what height you drop it like 5 inches its 2 seconds
Use the formula [ H = 1/2 G T2 ].-- Take the number of seconds to fall to the ground.-- Square the number (multiply it by itself).-- For height in meters, multiply by 4.9-- For height in feet, multiply by 16.1Note: This method doesn't account for air resistance. It works for compact, dense objects, like stones,books, or loaded boxes. It doesn't work for large, light objects, like paper, parachutes, or autumn leaves.