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If you toss 7 coins what is the probability of getting at least 4 heads?
Wiki User
∙ 14y ago
This is a Binomial Probability Distribution, with number of trials n=7, r = 4, 5, 6, & 7 (at least 4 is 4 or more), and probability p is 1/2 or 0.5. The related link gives the binomial probabilities and the values, which are added together. The values for r = 4, 5, 6, & 7 are 0.273, 0.164, .055, .008. These add to 0.5, so the probability of getting at least 4 heads with a coin tossed 7 times is 0.5 or 50%.
Wiki User
∙ 14y ago
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Suppose six coins are flipped then the probality of getting at least one tail?
The probability of getting at least one tail in a flip of six coins is the same as the probability of not getting all heads, which is 1 - (0.56), or 0.984375.
You toss 3 coins What is the probability that you get exactly 2 heads given that you get at least one head?
you toss 3 coins what is the probability that you get exactly 2 heads given that you get at least one head?
When tossing 5 coins simultaneously what is the probability that at least 1 head is showing?
Probability of no heads = (0.5)^5 = 0.03125Probability of at least one head = 1 - probability of no heads = 1 - 0.03125 = 0.96875
What is the probability of getting 6 heads in tossing 6 coins in 6 tosses?
The probability of tossing 6 heads in 6 dice is 1 in 26, or 1 in 64, or 0.015625. THe probability of doing that at least once in six trials, then, is 6 in 26, or 6 in 64, or 3 in 32, or 0.09375.
When tossing 5 coins simultaneously find the probability that at least 1 head is showing.?
This is easiest to solve by working out the probability that no heads show and subtracting this from 1 to give the probability that at least one head shows: Assuming unbiased coins which won't land and stay on their edge, the probability of head = probability of tail = ½ → probability no heads = probability 5 tails = ½^5 = 1/32 → probability of at least one head = 1 - 1/32 = 31/32 = 0.96875 = 96.875 % = 96 7/8 %
Suppose six coins are flipped then the probality of getting at least one tail?
The probability of getting at least one tail in a flip of six coins is the same as the probability of not getting all heads, which is 1 - (0.56), or 0.984375.
You toss 3 coins What is the probability that you get exactly 2 heads given that you get at least one head?
you toss 3 coins what is the probability that you get exactly 2 heads given that you get at least one head?
What is the probability of getting a least one tail when tossing eight fair coins?
The probability of getting at least 1 tails is (1 - probability of getting all heads) The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256
When tossing 5 coins simultaneously what is the probability that at least 1 head is showing?
Probability of no heads = (0.5)^5 = 0.03125Probability of at least one head = 1 - probability of no heads = 1 - 0.03125 = 0.96875
What is the probability of getting 6 heads in tossing 6 coins in 6 tosses?
The probability of tossing 6 heads in 6 dice is 1 in 26, or 1 in 64, or 0.015625. THe probability of doing that at least once in six trials, then, is 6 in 26, or 6 in 64, or 3 in 32, or 0.09375.
If you were to flip a coin 4 times what is the probability of getting heads at least one time?
As the question is "what is the probability of getting at least one head" the correct way to answer this is to ask what is the probability of not getting any heads and then subtract this from 1.The probability of not getting a head in 4 flips = 0.54 (i.e. 0.5 * 0.5 * 0.5 * 0.5) = 1/16.Therefore the probability of getting at least one head is 1 - 1/16 = 15/16.
What is the probability of getting at least 2 heads when flipping a coin 3 times?
.125
When tossing 5 coins simultaneously find the probability that at least 1 head is showing.?
This is easiest to solve by working out the probability that no heads show and subtracting this from 1 to give the probability that at least one head shows: Assuming unbiased coins which won't land and stay on their edge, the probability of head = probability of tail = ½ → probability no heads = probability 5 tails = ½^5 = 1/32 → probability of at least one head = 1 - 1/32 = 31/32 = 0.96875 = 96.875 % = 96 7/8 %
What is the probability of tossing at least one head with 3 coins?
3 coins can land in 8 different ways. Only one of these ways is all tails. So the probability of rolling at least one heads is 7/8 = 87.5% .
If 3 coins are tossed simultaneously the probability of getting at least 1head is?
3/8
What is probability of at least 2 heads on tossing 3 coins?
There are 8 permutations of three coins. Of these, 3 of them have two heads, so the probability of tossing two heads on three coins is 3 in 8, or 0.375. However, you said, "at least", so that includes the case of three heads, so the probability of throwing at least two heads is 4 in 8, or 0.5. T T T T T H T H T T H H * H T T H T H * H H T * H H H *
What is the probability of obtaining exactly five heads in six flips of a coin given that at least one is a head?
The probability that you will toss five heads in six coin tosses given that at least one is a head is the same as the probability of tossing four heads in five coin tosses1. There are 32 permutations of five coins. Five of them have four heads2. This is a probability of 5 in 32, or 0.15625. ----------------------------------------------------------------------------------- 1Simplify the problem. It asked about five heads but said that at least one was a head. That is redundant, and can be ignored. 2This problem was solved by simple inspection. If there are four heads in five coins, this means that there is one tail in five coins. That fact simplifies the calculation to five permutations exactly.
