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Acceleration = (change in speed) / (time interval)= (50 - 30) mph / 20 sec = (20 mi/hr) (1/3,600 hr/sec) (5,280 ft/mi) / (20 sec)= (20 x 5,280) / (3,600 x 20) (mi - hr - ft / hr - sec - mi - sec)= 1.4667 ft/sec2 (rounded, repeating)
4.05 ft/sec
The acceleration of gravity is 32.1 ft/sec2 .After 3 seconds, the rock's downward speed is (3 x 32.1) = 96.3 ft/sec.(96.3 ft/sec) x (1 mi / 5,280 ft) = (96.3 / 5,280) (ft - mi / sec - ft) = 0.0182 mile/sec (rounded)
(20 mi / hr) x (12 sec) x (5,280 ft / mi) x (1 hr / 3600 sec)= (20 x 12 x 5,280 / 3,600) (mi - sec - ft - hr / hr - mi - sec)= 352 ft
First change mi/hr into ft/sec. There 1 mi = 5280 ft and 1 hour = 3600 sec. 6 mi/hr = 6 * (5280 ft / 3600 sec) = 8.8 ft / sec To figure out how fast you travel any distance you divide the distance by time it took you. distance / time = speed 205 ft / time = 8.8 ft / sec Solving for time: time = 205 ft / (8.8 ft / sec) time = 23 sec
Acceleration = (change in speed) / (time interval)= (50 - 30) mph / 20 sec = (20 mi/hr) (1/3,600 hr/sec) (5,280 ft/mi) / (20 sec)= (20 x 5,280) / (3,600 x 20) (mi - hr - ft / hr - sec - mi - sec)= 1.4667 ft/sec2 (rounded, repeating)
4.05 ft/sec
The acceleration of gravity is 32.1 ft/sec2 .After 3 seconds, the rock's downward speed is (3 x 32.1) = 96.3 ft/sec.(96.3 ft/sec) x (1 mi / 5,280 ft) = (96.3 / 5,280) (ft - mi / sec - ft) = 0.0182 mile/sec (rounded)
(20 mi / hr) x (12 sec) x (5,280 ft / mi) x (1 hr / 3600 sec)= (20 x 12 x 5,280 / 3,600) (mi - sec - ft - hr / hr - mi - sec)= 352 ft
Velocity is an object's Speed + Direction. For example, a cannon ball fired up at 45o to the ground may have a speed of 1000 ft/sec. However, its forward Velocity is:(1000 ft/sec) x (Sine 45o) = (1000 ft/sec) x (.707)= 707 ft/secSo, the ratio of the horizontal Velocity to the instantaneous Speed of the object is the SINE value of the angle of motion relative to the Horizontal axis.But you have to remember that there is a Vertical component of the object's Speed as well. In this case, the ratio is the COSINE 45o , which happens to be .707 as well. So the ball is going forward at 707 ft/sec, and upward at 707 ft/sec. at the same time.
1484 m/s, 4868 ft/sec
First change mi/hr into ft/sec. There 1 mi = 5280 ft and 1 hour = 3600 sec. 6 mi/hr = 6 * (5280 ft / 3600 sec) = 8.8 ft / sec To figure out how fast you travel any distance you divide the distance by time it took you. distance / time = speed 205 ft / time = 8.8 ft / sec Solving for time: time = 205 ft / (8.8 ft / sec) time = 23 sec
If the rate of acceleration is constant, the average speed over the two feet is 187.5 mph (half of 375 mph). 187.5 mi/h x 5280 ft/mi ÷ 3600 sec/h = 275 ft/sec At that speed, the time it takes to go 2 ft. is (1 sec)/(275 ft) x 2 ft or about 7.27 ms (milliseconds).
First, convert 20mph to ft/sec. (20 * 5280) ÷ 3600 = 28.9333... ft/sec To find out how long it would take to travel 500 ft, divide 500 by 28.9333.. and you get 17.28 seconds
Both Velocity and Acceleration define of an object's rate of motion. Velocity defines how fast something is moving and, is measured in ft/sec, mi per hr, etc. Acceleration defines how fast the rate of speed (Velocity) is changing. When you push in the accelerator on a car, you make it go faster. Acceleration is measured in ft/sec/sec. OR how many ft/sec faster is it moving for every second that the acceleration is applied. EXAMPLE: The Acceleration due to Gravity is 32 ft/sec/sec. When you drop something, first released it starts to fall with 0 velocity; after one sec, is it falling at 32 ft/sec; after two seconds is it falling at 64 ft/sec., etc, etc, etc.
20 mi/h * (1 h / 3600 s) * (5280 ft / 1 mi) = 29.33 ft/sec
Miles per hour Kilometer per hour Ft per sec