Acceleration = (change in speed) / (time interval)= (50 - 30) mph / 20 sec = (20 mi/hr) (1/3,600 hr/sec) (5,280 ft/mi) / (20 sec)= (20 x 5,280) / (3,600 x 20) (mi - hr - ft / hr - sec - mi - sec)= 1.4667 ft/sec2 (rounded, repeating)
4.05 ft/sec
(20 mi / hr) x (12 sec) x (5,280 ft / mi) x (1 hr / 3600 sec)= (20 x 12 x 5,280 / 3,600) (mi - sec - ft - hr / hr - mi - sec)= 352 ft
The acceleration of gravity is 32.1 ft/sec2 .After 3 seconds, the rock's downward speed is (3 x 32.1) = 96.3 ft/sec.(96.3 ft/sec) x (1 mi / 5,280 ft) = (96.3 / 5,280) (ft - mi / sec - ft) = 0.0182 mile/sec (rounded)
First change mi/hr into ft/sec. There 1 mi = 5280 ft and 1 hour = 3600 sec. 6 mi/hr = 6 * (5280 ft / 3600 sec) = 8.8 ft / sec To figure out how fast you travel any distance you divide the distance by time it took you. distance / time = speed 205 ft / time = 8.8 ft / sec Solving for time: time = 205 ft / (8.8 ft / sec) time = 23 sec
Acceleration = (change in speed) / (time interval)= (50 - 30) mph / 20 sec = (20 mi/hr) (1/3,600 hr/sec) (5,280 ft/mi) / (20 sec)= (20 x 5,280) / (3,600 x 20) (mi - hr - ft / hr - sec - mi - sec)= 1.4667 ft/sec2 (rounded, repeating)
4.05 ft/sec
(20 mi / hr) x (12 sec) x (5,280 ft / mi) x (1 hr / 3600 sec)= (20 x 12 x 5,280 / 3,600) (mi - sec - ft - hr / hr - mi - sec)= 352 ft
The acceleration of gravity is 32.1 ft/sec2 .After 3 seconds, the rock's downward speed is (3 x 32.1) = 96.3 ft/sec.(96.3 ft/sec) x (1 mi / 5,280 ft) = (96.3 / 5,280) (ft - mi / sec - ft) = 0.0182 mile/sec (rounded)
The velocity of a ball thrown at 16 ft/sec is 16 ft/sec. This means that the ball is moving at a constant speed of 16 feet per second in a particular direction.
First change mi/hr into ft/sec. There 1 mi = 5280 ft and 1 hour = 3600 sec. 6 mi/hr = 6 * (5280 ft / 3600 sec) = 8.8 ft / sec To figure out how fast you travel any distance you divide the distance by time it took you. distance / time = speed 205 ft / time = 8.8 ft / sec Solving for time: time = 205 ft / (8.8 ft / sec) time = 23 sec
If the rate of acceleration is constant, the average speed over the two feet is 187.5 mph (half of 375 mph). 187.5 mi/h x 5280 ft/mi ÷ 3600 sec/h = 275 ft/sec At that speed, the time it takes to go 2 ft. is (1 sec)/(275 ft) x 2 ft or about 7.27 ms (milliseconds).
First, convert 20mph to ft/sec. (20 * 5280) ÷ 3600 = 28.9333... ft/sec To find out how long it would take to travel 500 ft, divide 500 by 28.9333.. and you get 17.28 seconds
Both Velocity and Acceleration define of an object's rate of motion. Velocity defines how fast something is moving and, is measured in ft/sec, mi per hr, etc. Acceleration defines how fast the rate of speed (Velocity) is changing. When you push in the accelerator on a car, you make it go faster. Acceleration is measured in ft/sec/sec. OR how many ft/sec faster is it moving for every second that the acceleration is applied. EXAMPLE: The Acceleration due to Gravity is 32 ft/sec/sec. When you drop something, first released it starts to fall with 0 velocity; after one sec, is it falling at 32 ft/sec; after two seconds is it falling at 64 ft/sec., etc, etc, etc.
The numerical ratio of velocity to speed of an object is always equal to or greater than 1. This is because velocity is a vector quantity that includes both magnitude (speed) and direction, while speed is a scalar quantity that only represents magnitude. If the object is moving in a straight line, the ratio will be 1. If the object is changing direction, the ratio will be greater than 1.
Miles per hour Kilometer per hour Ft per sec
60 mi/hr * 1 hr/60 min * 1 min/60 sec * 5280 ft/mi = 88 ft/sec; so 60 MPH is 88 ft/sec. Multiply 88 ft/sec * 6 sec = 528 ft.