49
49
9.8m/s(5)= 49
,033
The acceleration of gravity is 9.8 m/s2Speed after 3 sec = (9.8 x 3) = 29.4 m/s
49
29.4
49
9.8m/s(5)= 49
,033
The acceleration of gravity is 9.8 m/s2Speed after 3 sec = (9.8 x 3) = 29.4 m/s
The speed of the rock after 5 seconds, neglecting air resistance, can be determined using the equation: speed = initial velocity + acceleration * time. Since the initial speed is 0 m/s, and assuming the acceleration due to gravity is 9.81 m/s², the speed of the rock after 5 seconds would be 49.05 m/s.
The rock would have a speed of 49 m/s after 5 seconds of free fall due to gravity (assuming g = 9.81 m/s^2). This is because its speed increases by 9.81 m/s every second during free fall.
The rock's speed after 5 seconds would be approximately 49 m/s. This is calculated using the formula v = g * t, where v is the final speed, g is the acceleration due to gravity (9.8 m/s^2), and t is the time elapsed (5 seconds).
speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s
A pendulum will eventually come to a stop due to air resistance and friction, which absorb the pendulum's energy over time. The rate at which the pendulum's motion slows down depends on the amount of resistance it encounters and the initial energy imparted to it.
No, the acceleration is not the same for an object that is dropped and an object that is thrown. When an object is dropped, it experiences a constant acceleration due to gravity. When an object is thrown, its acceleration can vary depending on factors such as the initial velocity and direction.