90kph divided by 3 = 30 kph
avg. speed = distance traveled / timeso, 100 km / 1.25 hours = 80 km/hr
distance traveled=60 km.time =45 minutes=45/60 hrs=0.75 hrsthen speed =distance traveled/total time=60/ 0.75 km/hr=80 km/hr
Average Speed is the distance traveled divided by the time it took to travel that distance.In this case, the distance traveled is 240 km, and the time is 3hrs.You do the calculation. (your answer will have the unit km/hr)
90 minutes = 1.5 hours so speed = 320/1.5 km per hour = 213.33... recurring km per hour.
Speed in kph = 100/1.5
30 km/h x 3 h = 90 km
40/5 = 8 km/hr
avg. speed = distance traveled / timeso, 100 km / 1.25 hours = 80 km/hr
With constant velocity (v) the equation for distance can be d = vt, where d is the distance traveled (in miles), and t is the time (in hours). So at t= 2 hr, d = 90 mi, solve for v = (90 mi)/(2 hr) = 45 mi/hr (or mph). Check this at 5 hours: d = (45 mi/hr)*(5 hr) = 225 mi, which checks with the original problem.
Speed = distance/time km/hr = 90km/3hr 90/3=30 30km/hr
90 Km/Hr
distance traveled=60 km.time =45 minutes=45/60 hrs=0.75 hrsthen speed =distance traveled/total time=60/ 0.75 km/hr=80 km/hr
avg speed is = total distance divided by total time so its 160/2.5= 64miles/hr
Average Speed is the distance traveled divided by the time it took to travel that distance.In this case, the distance traveled is 240 km, and the time is 3hrs.You do the calculation. (your answer will have the unit km/hr)
speed = distance / time = 80 km / 0.75 hr = 80 km / ¾ hr = 80 × 4/3 km/h = 106 2/3 km/h ≈ 107 km/h
No. Distance is dependent on both length of travel and speed of travel. For example, If car A leaves location X at a certain time, and travels at 200km/hr for two hours, it travels 400km. If car B leaves the same location at the same time, and travels 50km/hr for four hours, it travels 200km. As you can see, car A traveled for half the time car B traveled while doubling its total distance traveled.
Acceleration = (change in speed) / (change in time) = [ (54 - 36) km/hr ] / (10 sec) = (18 km/hr) /(10 sec) = (1.8 km/hr-sec) x (3,600 sec / hr) = (1.8 x 3,600) (km - sec / hr2 - sec) = 6,480 km / hr2 Average speed during the 10 seconds = (36 + 54) / 2 = 90/2 = 45 km/hr Distance = (average speed) x (time) = (45 km/hr) x (10 sec) x (1 hr / 3,600 sec) = (45 x 10 / 3,600) (km - sec - hr / hr - sec) = 0.125 km = 125 meters