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As for example in the equation: y = 2x+5 the slope is 2 and the y intercept is 5

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Q: In the slope- intersect equation of a line which part of the equation gives the y coordinate of the point where the line crosses the y axis?
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In the slope-intercept equation of a line which part of the equation gives the y-coordinate of the point where the line crosses the y-axis?

The slope intercept equation also called the y intercept equation. It isy=mx+b in which x and y are coordinates, m is the slope of the line, and b is the y-intercept. so b would be the y-coordinate that intersects the y-axis.


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The point slope form of a line is the equation y-y_1=m*(x-x_1) where y_1 and x_1 are coordinate for some point the line intersect and m is the slope. Just plugging in your given numbers gives the equation y+4=-2*(x+8)


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Th formul for slope-intercept is y=mx+b. y= the y-coordinate m= the slope x= the x-coordinate b= the y-intercept Therefore if your equation was y=3x+5 then the coefficient that gives the slope is 3.


How do you graph 2a plus 3b equals 6?

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How do you determine if a certain point lies on a given line by just having the coordinates for the point and the equation of the line?

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What is the x-intercept of y5x-10?

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Integration results in an equation which gives the area under the original equation between the bounds. Derivation results in an equation which gives the slope of the original line at any point.


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to find b in y=25x + b you can substitute in one of the coordinate pairs for x and y. for example,you can substitute 7 for x and 175 for y.this gives 174=(25)(7) + b .solve this equation for b and substitute that value into the expression


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How do you graph a line if given the equation in slope intercept form?

When you are working with y=mx+b, (x,y) is a coordinate on the line, m is the slope, and b is the y intercept. You simply plot the y intercept and then pick a random value for x or y and solve the equation. This gives you two points on the line that you can connect creating a continuous line on the plane.