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Q: In the sum 8 plus 88 plus 888 plus 888888888888888888888 what are the last two digits in the tens and units place?

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You test if the last two digits are divisible by 4. If the digit in the tens' place is odd, the digit in the units place must be 2 or 6. If the digit in the tens' place is even, the digit in the units place must be 0, 4 or 8.

The units digits start with 8 and go down in steps of 2. The units digit repeats every 5 multiples, The last pair of digits repeat every 25 multiples.

If the number formed by the last three digits is divisible by 8. This requires that: if the digit in the hundreds place is even, the last two digits must form a number divisible by 8 and if the digit in the hundreds place is odd, the last two digits must form a number divisible by 4 but not by 8.

200

2. The last two zeros are place holders.

4. The last two digits are simply place holders.

Pi is irrational, there are no last digits, the number does not end.

There are no last 14 digits in pi. The first 14 are 3.14159265358979.

are the last TWO digits of 5347. 5, 3, 4, and 7 are all digits of the number 5347.

1, 3, and 9 all are significant. The zeros are merely place holders and thus, not significant.

Consider it a convention. Basically, it doesn't make much sense to register many more digits after a digit that is uncertain. Another common convention is to enclose uncertain digits - often the last two digits shown - in parentheses, for example, 6.67384(80)Ã—10âˆ’11 for the gravitational constant in SI units.,

The last three digits of 16,123 are "1," "2" and "3," in that order.

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