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integer 1 = x

integer 2 = y

x + y = 2

x - y = 8

solve 2nd eq. for x gives: x = 8 +y

substitute into first eq

(8+y)+y=2

8+2y = 2

move the 8 by subtracting the 8 from both sides of the equation

2y=-6

divide by 2

y = -3

take y and put back into any of the 2 equations you began with

x+y = 2

x + -3 = 2

add 3 to both sides of the equation

x = 5

check your solution by taking x and y and putting into any equation and check the result

5 + -3 = 2 CHECK

5 - (-3) = 8 CHECK integer 1 = x

integer 2 = y

x + y = 2

x - y = 8

solve 2nd eq. for x gives: x = 8 +y

substitute into first eq

(8+y)+y=2

8+2y = 2

move the 8 by subtracting the 8 from both sides of the equation

2y=-6

divide by 2

y = -3

take y and put back into any of the 2 equations you began with

x+y = 2

x + -3 = 2

add 3 to both sides of the equation

x = 5

check your solution by taking x and y and putting into any equation and check the result

5 + -3 = 2 CHECK

5 - (-3) = 8 CHECK

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15y ago
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Q: Integers have a sum of 2 and a difference of 8?
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