integer 1 = x
integer 2 = y
x + y = 2
x - y = 8
solve 2nd eq. for x gives: x = 8 +y
substitute into first eq
(8+y)+y=2
8+2y = 2
move the 8 by subtracting the 8 from both sides of the equation
2y=-6
divide by 2
y = -3
take y and put back into any of the 2 equations you began with
x+y = 2
x + -3 = 2
add 3 to both sides of the equation
x = 5
check your solution by taking x and y and putting into any equation and check the result
5 + -3 = 2 CHECK
5 - (-3) = 8 CHECK integer 1 = x
integer 2 = y
x + y = 2
x - y = 8
solve 2nd eq. for x gives: x = 8 +y
substitute into first eq
(8+y)+y=2
8+2y = 2
move the 8 by subtracting the 8 from both sides of the equation
2y=-6
divide by 2
y = -3
take y and put back into any of the 2 equations you began with
x+y = 2
x + -3 = 2
add 3 to both sides of the equation
x = 5
check your solution by taking x and y and putting into any equation and check the result
5 + -3 = 2 CHECK
5 - (-3) = 8 CHECK
8 and -8 8+(-8)=0 8-(-8)=16
-8 minus 10 -8 plus 10
-8+10=2
-3, 5
Given:a + b = 2a - b = 8Then:a = b + 8∴ (b + 8) + b = 2∴ 2b = -6∴ b = -3∴ a = 5
8 and -8 8+(-8)=0 8-(-8)=16
Three and Five.
5 and -3
-8 minus 10 -8 plus 10
-8+10=2
-3, 5
-8 and 10.---------------------------8 + 10 = 2-8 - 10 = -18
8 and -8; 8 + (-8) = 8 - 8 = 0, and 8 - (-8) = 8 + 8 = 16
5 + (-3) = 2 5 - (-3) = 8 The two numbers are therefore 5 and -3.
15 and 8
if you were to do it as a fraction the two integers would be 1 and a half. your welcome:] !!!
Given:a + b = 2a - b = 8Then:a = b + 8∴ (b + 8) + b = 2∴ 2b = -6∴ b = -3∴ a = 5