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Q: Is this statement true of false AB is the hypotenuse of?

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true

Assuming you mean side AB is 5: If angle B is the right angle, side AC is the hypotenuse and is of length 6. If angle A is the right angle, side BC is the hypotenuse and is of length sqrt(52 + 62) ~= 7.81 Angle C cannot be the right angle as then side AB would be the hypotenuse but the hypotenuse is the longest side and side AB is shorter than AC.

FALSE B CAN ONLY RECEIVEVE O AND B SAFELY BECAUSE OF THAT A IN AB, THEMPERSON CAN'T RECEIVE IT

sqrt(ab^2 + bc^2)

If CB is the hypotenuse, then AB measures, √ (62 - 52) = √ 11 = 3.3166 (4dp) If AB is the hypotenuse then it measures, √ (62 + 52) = √ 61 = 7.8102 (4dp)

Pythagoras ' theorem states that in a right angled triangle ABCAB2+BC2 = AC2, where AB and BC are the perpendicular sides of the triangle and AC is the hypotenuse(the longest side).

If angle ACB is the right angle then ab is the hypotenuse. Then, (ab)2 = 62 + 92 = 36 + 81 = 117 ab = √117 = 10.8 (3 sf) If angle BAC is the right angle then ab is one leg of a right angled triangle with bc the hypotenuse. 92 = 62 + (ab)2 : (ab)2 = 92 - 62 = 81 - 36 = 45 ab = √45 = 6.71 (3 sf)

15

If the sides of the triangle are 20 and 15 then by using Pythagoras' theorem the length of the hypotenuse works out as 25 units of measurement.

The length is sqrt(61) units.

This is a statement, not question.

Suppose triangle ABC is right angled at C. Suppose you are given that the angle at B is theta. Thenif you know the length of AB (the hypotenuse), thenBC = AB*cos(theta) andAC = AB*sin(theta)if you know the length of BC, thenAB = BC/cos(theta) andAC = BC*tan(theta)if you know the length of AC, thenAB= AC/sin(theta) andBC = AC/tan(theta)

This is false. The only way this would be true is if P=Q. Then AP+BP=AQ+QB=AB. The only thing that could be said, I guess, would be that AB intersects the angles PAQ and PBQ.

If those are the legs, the hypotenuse is √113

Zero.For instance, given a right triangle with points ABC. where AC is the hypotenuse, then to find the angle between AB, we take sin(AB/AC), where AB is the distance between points A and B, and AC is the distance between A and C. If we replace AB with 0, the equation would be sin(0/AC). Sine of zero is always zero.

True when the rays represent vectors. Not always true otherwise. This is partly because with vectors ab is not the same as ba whereas with ordinary lines such a distinction is not important. False

Which statement describes the blood type of a person with the alleles IAi? It is type AB because I and i are codominant. It is type AB because A and i are codominant. It is type A because i is dominant and A is recessive. It is type A because A is dominant and i is recessive.

ab 25 of august 2010 it is true from wafaq ul madaris

Let consider the right triangle ABC with hypotenuse AB and heigth AC then base is BC Pythagorean theorem states that AB2=AC2+BC2 so BC2=AB2-AC2 then BC=sqrt(AB2-AC2)

Not too sure of the question and answer needed but if it is a right angle triangle with an hypotenuse of 25 units then to comply with Pythagoras; theorem it sides must be 15 units and 20 units.

In a right angled triangle its hypotenuse when squared is equal to the sum of its squared sides which is Pythagoras' theorem for a right angle triangle.

Take a right angled triangle ABC with the right angle at B, so that AC is the hypotenuse. Let AC be 1 unit long. Using the angle CAB, the length of AC and the trigonometric ratios: sin = opposite/hypotenuse ⇒ sin CAB = AB/AC = AB/1 = AB cos = adjacent/hypotenuse ⇒ cos CAB = BC/AC = BC/1 = BC Using Pythagoras: AB2 + BC2 = AC2 ⇒ (sin CAB)2 + (cos CAB)2 = 12 ⇒ sin2θ + cos2θ = 1

Consider a right triangle ABC as shown below. The right angle is at B, meaning angle ABC is 90 degrees. With the editor I have, I am not able to draw the line AC but imagine it to be there. By pythagorean theorem AC*2 = AB*2 + BC*2. The line AC is called the hypotenuse. Consider the angle ACB. The cosine of this angle is BC/AC, the sine is AB/AC and tangent is AB/BC. If you consider the angle BAC, then cosine of this angle is AB/AC, the sine is BC/AC and tangent is BC/AB. In general sine of an angle = (opposite side)/(hypotenuse) cosine of an angle = (adjacent side)/(hypotenuse) tangent of an angle = (opposite side)/(adjacent side) |A | | | | | | |______________________C B

Yes.

AB