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Is 0 an interval

Updated: 9/22/2023
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11y ago

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not really

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11y ago
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Q: Is 0 an interval
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Related questions

What interval did you choose for your graph?

i personally chose 0 an my interval


What characteristics of the graph of a function by using the concept of differentiation first and second derivatives?

If the first derivative of a function is greater than 0 on an interval, then the function is increasing on that interval. If the first derivative of a function is less than 0 on an interval, then the function is decreasing on that interval. If the second derivative of a function is greater than 0 on an interval, then the function is concave up on that interval. If the second derivative of a function is less than 0 on an interval, then the function is concave down on that interval.


What are mixed numbers between 0 and 2 with an interval of 18?

There are no mixed numbers between 0 and 2 with an interval of 18.


What does interval on a line graph?

wha is the interval on a line graph, scale from 0-25?..


What are the limitation of the probability?

Probability of an even must lie in the closed interval [0, 1].Probability of an even must lie in the closed interval [0, 1].Probability of an even must lie in the closed interval [0, 1].Probability of an even must lie in the closed interval [0, 1].


Can probability be less than 0?

No, it must be a number in the interval [0, 1].


What is probability as a number?

It is a number in the interval [0, 1].


How do you write a is positive as an interval notation?

0 < a < ∞


If the derivative of a function equals xsquared - 2divided byx on which intervals is f decreasing?

f(x) is decreasing on the interval on which f'(x) is negative. So we want: (x2-2)/x<0 For this to be true either the numerator or the denominator (but not both) must be negative. On the interval x>0, the numerator is negative for 0<x<sqrt(2) and the denominator is positive for all x>0. On the interval x<0, the denominator is negative for all values on this interval. The numerator is positive on this interval for x<-sqrt(2). So, f' is negative (and f is decreasing) on the intervals: (-infinity, -sqrt(2)), (0, sqrt(2))


What is the integral of sin t dt with the interval x 0?

Let g(x) = interval [0, x] of sin t dt, and f(t) = sin t. Since f(t) is a continuous function, the part one of the Fundamental Theorem of Calculus gives, g'(x) = sin x = f(x) (the original function). If you are interested in the interval [x, 0] of sin t dt, then just put a minus sign in front of the integral and interchange places of 0 and x. So that, g(x) = interval [x, 0] of sin t dt = -{ interval [0, x] of sin t dt}, then g'(x) = - sin x.


Why can the number 0.56 be the probability of an event?

It is a number in the interval [0, 1].


How do you write in interval notation x is positive?

Positive: (0, infinity)Nonnegative: [0, infinity)Negative: (-infinity, 0)Nonpositive (-infinity, 0]