Depends what f is....
No. Its domain (or support) is from 0 to infinity.
Yes.
There are 24 possible functions: One of these is f(0) = 2 f(0.5) = 4.5 f(2) = 0.5 f(3) = 0 The four numbers in the range can be placed opposite the domain in any order.
The domain of f is x is R (if imaginary roots are permitted, and there is nothing in the question to suggest otherwise). The domain of g is R excluding x = 5 So the domain of f + g is R excluding x = 5 and the domain of f/g is R excluding x = 0
A quadratic function: f(x) = ax2 + bx + c = 0, where a ≠ 0. Domain: {x| x is a real number}, or in the interval notation, (-∞, ∞). Range: If a > 0, {y| y ≥ f(-b/2a), the y-coordinate of the vertex} or [f(-b/2a), ∞). If a < 0, {y| y ≤ f(-b/2a), the y-coordinate of the vertex} or (-∞, f(-b/2a)]. * * * * * Alternative answer: The domain is anything you chose it to be. For example, the integers between 2.5 and 4.7 (ie 3 and 4) and the real numbers between 4.8 and 5.0. Then the range would be the values of f(x) which corresponded to the values of x in the domain.
The only way is to look at the definition of the function. A function is a one-to-one or many-to-one mapping from a set S to a set T, which may be the same as S. These sets need need not be numerical. The domain could be the residents of a town with the range as the first two letters of their first name!Definitional gaps in the domain can always be removed by definition. For example,the function f(x) = 1/x must have a domain that excludes x = 0.However, f(x) = 1/x when x?0, f(0) = 17.3 (for example) does include 0 in its domain.
The domain of a function is just all the x-values that have a corresponding y-value. Typically, you need to check for discontinuities or vertical asymptotes. For example, any x value that causes the denominator of a fraction to be 0 must be excluded from the domain, since you can't divide by 0. A simple case would be f(x) = 1 / x If x = 0 , the denominator is 0 and the function is undefined; all other values of x have a corresponding value for f(x), so the domain would be x < 0 and x > 0, or (-∞, 0) U (0, ∞). >>M.T.<<
X>0
Domain, in math terms, is the set of possible x values. This changes with your function. f(x)=x, for example, has a domain of negative infinity to infinity. However, f(x)=squareroot of x can only be positive, as otherwise it would go to imaginary numbers. Hence, its domain is 0 to inifinity.
The domain of a function is the set of input values for which the function is defined. The domain does not normally have a single value as such, but will typically be described through one or more intervals.For example, consider the real function f(x) := 1 / x.f is defined for all real values of x except zero, so the domain of f will be the combination of two intervals -infinity < x < 0 and 0 < x < +infinity.
Domain = set of points at which a function exists Range = set of points which are mapped to by the function For example, if f(t) = 1/t => domain is all real numbers except for t=0, since 1/0 is an mathematical error and: range is all real numbers except for f(t) = 0 since you cannot actually obtain this value by inputting a value for t.
If the function of the variable x, is f(x) then the roots are all the values of x (in the relevant domain) for which f(x) = 0.