No.
111 numbers between 5 and 1000 are divisible by 9
There are many numbers between 500 and 1000 divisible by 3 and 9. Any number divisible by 9 is divisible by 3. How about 900?
There are 10 palindromes divisible by 9 between 1000 and 9999.
The first number in this range divisible by 9 is 9 itself...9 = 1 x 9 The last number in the range is 999 = 111 x 9 So there are 111 numbers between 1 and 1000 that are divisible by 9.
No, neither one.
None of the numbers you listed are evenly divisible by 1000.
9000 / 9 = 1000 9000 / 10 = 900
9000 divided by 5 is 1800 divided by 4 is 2250 divided by 9 is 1000
think I suppost to know.
There are 1,000 positive integers between 1,000 and 9,999, inclusive, that are divisible by nine.
This would be the same as asking how many times does nine go into 1000, since every integer divisible by 9 is just every ninth number, so you divide by 9 and then truncate, since the fractional portion does not represent getting to another integer, yet. 1000/9 = 111.11111...., so the answer is 111.
Alright, buckle up buttercup. The divisibility rules for 1000 times 1000 from 2 to 11 are as follows: it's divisible by 2 because it ends in 000, divisible by 3 because the sum of the digits is divisible by 3, divisible by 4 because the last two digits form a number divisible by 4, divisible by 5 because it ends in 000, divisible by 6 because it's divisible by 2 and 3, divisible by 7 because I said so, divisible by 8 because the last three digits form a number divisible by 8, divisible by 9 because the sum of the digits is divisible by 9, divisible by 10 because it ends in 000, and divisible by 11 because...well, just trust me on this one.