Q: Is 123 divisible by 2 and 3?

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No. 123 is only divisible by: 1, 3, 41, 123.

It is divisible by 3. 3 X 41 = 123

only 123 is divisible by 3. 123 / 3 = 41

246 is divisible by 1, 2, 3, 6, 41, 82, 123, 246.

To be divisible by 6, the number must be divisible by both 2 and 3:To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8};To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3.As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3.If the number is not divisible by 2 or 3 (or both) then the number is not divisible by 6.examples:126Last digit is even so it is divisible by 2 1 + 2 + 6 = 9 which is divisible by 3, so it is divisible by 3â†’ 126 is divisible by both 2 and 3, so it is divisible by 6124Last digit is even so it is divisible by 2 1 + 2 + 4 = 7 which is not divisible by 3, so it is not divisible by 3â†’ 126 is divisible by 2 but not divisible by 3, so it is not divisible by 6123Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 3 = 6 which is divisible by 3, so it is divisible by 3â†’ 123 is divisible by 3 but not divisible by 2, so it is not divisible by 6121Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 1 = 4 which is not divisible by 3, so it is not divisible by 3â†’ 121 is not divisible by either 2 or 3, so it is not divisible by 6

yes it is 41

No, it's divisible by 3.

Yes.

5

123 is not a prime number because it is divisible by 41 and 3. (123/41=3 and 123/3=41)A prime number is any number that is only divisible by two factors, one and itself.123 is a composite number because its factors are 1, 3, 41, and 123.

if the number is a 2 or more diget number, you add up all of the numbers in the number and when you have the sum, if the sum is divisible by 3 , the whole number is divisible by three EX. 123=6, 6 is divisible by 3 so 123 is divisible by three 447=15 is divisible by 3 so 447 is divisible by 3 989=26 is *NOT* divisible by 3 so 989 is not divisible by three this truly does work for every single number

369/3 = 123

Yes and the result is 123.

369 is divisible by 1, 3, 9, 41, 123, and 369.

No.371/3 = 123 2/3 (one hundred and twenty three and two thirds).

114

No. It is only divisible by: 1 3 9 41 123 and 369.

No, 492 is only divisible by 1, 2, 3, 4, 6, 12, 41, 82, 123, 164, 246, 492.

1, 2, 3, 6, 9, 18, 41, 82, 123, 246, 369, 738.

NO!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 2 is divisible by 3

416 is divisible by 2 but is not divisible by 3.

The greatest common factor of 123 and 234 is 3.123: the digits (1, 2, 3) add up to 6.234: the digits (2, 3, 4) add up to 9.So both 6 and 9 are divisible by three.More formally:The prime factors of 123 are 3 and 41, while the prime factors of 234 are 2, 3, 3, and 13. The intersection of [3, 41] and [2, 3, 3, 13] is [3], therefore the Greatest Common Factor (GCF) of 123 and 234 is 3.

123/3 - 2, 123/3 and 123/3 + 2 ie 39, 41 and 43.

Yes, it is divisible by 2 because it ends with 2, it is also divisible bye 3 because 1+3+2=6. 6 is divisible by 3, therefor 132 is divisible by 3.

No. 483 is not divisible by 6.A number is divisible by 6 if it is divisible by both 2 and 3.It is divisible by 2 if it is even and it is divisible by 3 if the sum of the digits is a multiple of 3.483 is not divisible by 6 since it is not divisible by 2 although it is divisible by 3.

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