123 is not divisible by 2
it is divisible by 3
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∙ 2011-11-12 23:59:28well any multiple of 123 would be divisable by 123. Ex 123,246,369,492,615,738... but if your asking what 123 can be divided by its' 1 and itself, therefore making it a prime number 177
369 is divisible by 1, 3, 9, 41, 123, and 369.
Yes, it is divisible by 2 because it ends with 2, it is also divisible bye 3 because 1+3+2=6. 6 is divisible by 3, therefor 132 is divisible by 3.
No, 120 or 126 are divisible by 6.
123 is a composite number because it is divisible by 3. A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1, 2, and 0. 1, 2, and 0 have a different name.
No. 123 is only divisible by: 1, 3, 41, 123.
only 123 is divisible by 3. 123 / 3 = 41
246 is divisible by 1, 2, 3, 6, 41, 82, 123, 246.
No, 369 is divisible by 3.
Yes.
No, it's divisible by 3.
5
well any multiple of 123 would be divisable by 123. Ex 123,246,369,492,615,738... but if your asking what 123 can be divided by its' 1 and itself, therefore making it a prime number 177
369/3 = 123
if the number is a 2 or more diget number, you add up all of the numbers in the number and when you have the sum, if the sum is divisible by 3 , the whole number is divisible by three EX. 123=6, 6 is divisible by 3 so 123 is divisible by three 447=15 is divisible by 3 so 447 is divisible by 3 989=26 is *NOT* divisible by 3 so 989 is not divisible by three this truly does work for every single number
369 is divisible by 1, 3, 9, 41, 123, and 369.
No.371/3 = 123 2/3 (one hundred and twenty three and two thirds).