not prime
as can be divided by 10 and 13 and others
so is composite
The prime factorization of 130 is 2x5x13.
No prime numbers end in 0. 130 is a composite.
By definition, any multiple of 130 must have 130 as a factor. Therefore no such number can be a prime.
It is 13 and as a product of its prime factors: 2*5*13 = 130
The prime factorization of 130 is 2 x 5 x 13.
No
To find the prime factors of 130, we start by dividing it by the smallest prime number, which is 2. 130 divided by 2 is 65. Next, we divide 65 by 5, another prime number, to get 13. Finally, 13 is a prime number itself. Therefore, the prime factors of 130 are 2 x 5 x 13.
The prime numbers between 130 and 140 are 131, 137, and 139.
If there were two prime factors of 130, then they would have to be the only possible factors of 130.If either of them could be broken down to smaller factors, it wouldn't be a prime number.In addition to '1' and '130' ... 2, 5, 10, 13, 26, and 65 are also factors of 130. So there can't be two prime factors.
Prime factorization of 130 is 2x5x13, (or 21x51x131 if unnecessary exponents must be shown).
No, it can be divided by 5. (Ex 130 divided by 5=26)
5