yes 1428/3 = 476
if you add numbers up and you can divide sum by 3 then it is divisible by 3
1+4+2+8 = 15 which is divisible by 3
Yes. It equals 357
All multiples of 1,362 which is an infinite number.
1 X 1428= 1428 714 X 2= 1428 238 X 6= 1428 178.5 X 8=1428 1429 - 1=1428 1427 + 1=1428 1430 - 2=1428 1426 + 2=1428 1434 - 6=1428 1422 + 6=1428 1436 - 8=1428 1420 - 8=1428 There are more ways to get 1428, but I just don't have the time. By the way I did all of this with a calculator on my computer so whoever asked this question was acting pretty dumb.
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.
It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.
1501 - 1428 = 73
1428 + 6178 = 7606
A number is divisible by 3 if the sum of its digits is divisible by 3.
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
3 is not divisible by 126. 126 is divisible by 3.
NO. 313 is not divisible by 3.A number is divisible by 3 if the sum of the digits is divisible by 3.313 = 3 + 1 + 3 = 7Note: 7 not divisible by 3 thus, 313 is not divisible by 3.
1x6,743 not divisible by 2 no its not divisible by 3????