Yes, because 3 times 5 equals 15 and 5 times 3 equals 15.
15 is divisible by 3 and 5, because 15/3=5, and 15/5=3.
A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3
15
15 is the smallest number divisible by both 3 and 5
Since both 3 and 5 are prime numbers, only numbers that are multiples of its product are the numbers that are divisible by both. 15 is the LCM of 3 and 5 and hence all multiples of 15 are divisible by both 3 and 5
The number is divisible by both 3 and 5. A number is divisible by 3 if the sum of the digits are and by 5 if the last digit is 0 or 5. Ex: 863,145 Non Ex: 93,460
15 is divisible by 3 and 5.
The number that is between 40 and 50 and is divisible by both 3 and 5 is 45. To determine if a number is divisible by both 3 and 5, you must ensure it is divisible by both 3 and 5 without leaving a remainder. In this case, 45 meets this criteria as it is divisible by both 3 (45 ÷ 3 = 15) and 5 (45 ÷ 5 = 9).
'15' Hence 3 x 5 = 15 or 15/3 = 5 or 15/5 = 3
They are both divisible by 3, 5 and 15.
There is no such number. If you have any such number, n, that is divisible by 3 and 5 then n + 15 is larger, and is divisible by both. And you can add another 15 to that number, and then to that, for ever more.
Numbers that are divisible by both 3 and 5 must be multiples of the least common multiple of 3 and 5, which is 15. Therefore, any number that is divisible by 15 will also be divisible by both 3 and 5. This includes numbers like 15, 30, 45, 60, and so on.