10 is divisible by both 5 and 2, as are any multiples of 10.
60
It is 90.
60
The number is 90.
'15' Hence 3 x 5 = 15 or 15/3 = 5 or 15/5 = 3
10 is divisible by both 5 and 2, as are any multiples of 10.
Because 10 is divisible by both 2 and 5
60
If its divisible by 5 AND 2 it must be divisible by 10 So you just have to pick the only number between 21 and 39 that's divisible by 10
Multiples of 10 between 1000 and 9990 Any four-digit number ending in zero.
There are no numbers between 900 and 1,100 that are divisible by 10 but not by two.
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
10
It is 90.
A number divisible by both 2 and 5 will be divisible by their product (2 x 5), which is 10. Any number divisible by 10 ends in 0. The only number listed that ends in 0 is 110.
To determine if 610 is divisible by both 6 and 10, we need to check if it is divisible by both 6 and 10 individually. For 6, we check if 610 is divisible by 2 and 3. Since 610 is even but not divisible by 3, it is not divisible by 6. For 10, we check if 610 ends in 0, which it does not. Therefore, 610 is not divisible by 10 either.