81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
Here's a mathematical trick. Any number wholly divisible by 3 has the sum of its digits equal to 3 or a multiple of 3. 199 : 1 + 9 + 9 = 19....NOT divisible by 3 209 : 2 + 0 + 9 = 11....NOT divisible by 3 390 : 3 + 9 + 0 = 12....YES, this is divisible by 3 499 : 4 + 9 + 9 = 22....NOT divisible by 3 Note : 390 ÷ 3 = 130
199 - 9% = 199 x (1 - (9/100)) = 199 x 0.91 = 181.09.
1, 5, 199, 995.
1, 3, 199, 597.
19 divisible by 5, 14 divisible by 7. Of these, 3 divisible by both.
No, it would be divisible by ten.
Yes because 597/3 = 199
Not evenly. The answer would be 18 remainder 1.
NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)
No it is not divisible by 9 .
No - any number divisible by 9 will have the sum of its digits divisible by 9.