If the sum of each digit of a number is divisible by three ((1 + 1 + 1 + 0)/3 = 1) and it gives an integer, and the number is divisible by 2 (1110/2 = 555) and also gives an integer, then the number is divisible by 6.So, yes.
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
No it is not divisible by 9 .
9 is divisible by both 3 and 9
No, 343 is not divisible by 9.
If the sum of each digit of a number is divisible by three ((1 + 1 + 1 + 0)/3 = 1) and it gives an integer, and the number is divisible by 2 (1110/2 = 555) and also gives an integer, then the number is divisible by 6.So, yes.
1110
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
No it is not divisible by 9 .
No - any number divisible by 9 will have the sum of its digits divisible by 9.
Yes, 441 is divisible by 9. To determine if a number is divisible by 9, you can add up its digits. In this case, 4 + 4 + 1 = 9, which is divisible by 9. Therefore, 441 is divisible by 9.
To be divisible by 15, it must also be divisible by 3 and by 5. To be divisible by 3, the sum of the digits must be divisible by 3; to be divisible by 5, the number must end with a zero or a five. Considering all these criteria, I guess that number would be 1110.
9 is divisible by both 3 and 9
No, and it is not divisible by 9 either!
it is not divisible by 9, errp
No, 998876 is not divisible by 9.