No, 231 is only divisible evenly by: 1, 3, 7, 11, 21, 33, 77, 231.
2 + 3 + 1 = 6, which is divisible by 3, so 231 is divisible by 3. Divide to get 231 = 77 Hard to miss that this is divisible by 7, so we get 231 = 3*7*11
All multiples of 6 Numbers are evenly divisible by 6 if they are evenly divisible by both 2 AND 3. Even numbers are always evenly divisible by 2. Numbers are evenly divisible by 3 if the sum of all the individual digits is evenly divisible by 3. For example, the sum of the digits for the number 3627 is 18, which is evenly divisible by 3 but 3627 is an odd number so the number 3627 is not evenly divisible by 6
693 is evenly divisible by 3. You can tell that at a glance because every one of its digits is evenly divisible by 3.
939 is evenly divisible by 3 939 is divisible by 8, but not evenly, quotient is 117, remainder is 3
It is not evenly divisible.
434 is evenly divisible by 2.It is not evenly divisible by 3, 6, or 9.
Not evenly. A number is divisible by 3 if the sum of its digits is divisible by 3.
It is divisible by 3.
no it is divisible by 3 and 231
It is divisible by 10, but not by 3.
All multiples of 6 Numbers are evenly divisible by 6 if they are evenly divisible by both 2 AND 3. Even numbers are always evenly divisible by 2. Numbers are evenly divisible by 3 if the sum of all the individual digits is evenly divisible by 3. For example, the sum of the digits for the number 3627 is 18, which is evenly divisible by 3 but 3627 is an odd number so the number 3627 is not evenly divisible by 6