Yes: 231 / 3 = 77
No, 231 is only divisible evenly by: 1, 3, 7, 11, 21, 33, 77, 231.
2 + 3 + 1 = 6, which is divisible by 3, so 231 is divisible by 3. Divide to get 231 = 77 Hard to miss that this is divisible by 7, so we get 231 = 3*7*11
All multiples of 6 Numbers are evenly divisible by 6 if they are evenly divisible by both 2 AND 3. Even numbers are always evenly divisible by 2. Numbers are evenly divisible by 3 if the sum of all the individual digits is evenly divisible by 3. For example, the sum of the digits for the number 3627 is 18, which is evenly divisible by 3 but 3627 is an odd number so the number 3627 is not evenly divisible by 6
939 is evenly divisible by 3 939 is divisible by 8, but not evenly, quotient is 117, remainder is 3
693 is evenly divisible by 3. You can tell that at a glance because every one of its digits is evenly divisible by 3.
It is not evenly divisible.
It is divisible by 3.
no it is divisible by 3 and 231
Not evenly. A number is divisible by 3 if the sum of its digits is divisible by 3.
434 is evenly divisible by 2.It is not evenly divisible by 3, 6, or 9.
It is divisible by 10, but not by 3.
It is not evenly divisible by 3. 10867/3 = 3622.333333333