It is evenly divisible by 2 and 10 but not by 3 and 9.
From that list of choices, 770 is evenly divisible by 2, 5, and 10, but not by 3 or 9.
The number 319 is evenly divisible only by 11 and 29.
712 is divisible by 2 because the digit at ones place is an even number. 712 is not divisible by 3 because the sum of the numbers(7+1+2=10) is not divisible by 3. 712 is divisible by 4 as the last two digits(12) are divisible by 4. 712 is not divisible by 5 because the last digit is neither 5 nor 0. 712 is not divisible by 6 because it is not divisible by 3. 712 is not divisible by 10 because the last digit is not 0.
An integer that is divisible by 100 with a remainder. The answer should be a whole number as well.eg. 3/100 = 0.03therefore 3 is not evenly divisible by 100300/100 = 3therefore 300 is evenly divisible by 100
Yes, but not evenly.
It is evenly divisible by 2 and by 3.
It is evenly divisible by 2 and 10 but not by 3 and 9.
No. Ten is not evenly divisible by three.
Only divisible by 5 evenly
Yes. Every number is divisible by every other number except 0. Therefore the answer is yes. If you actually meant is 834 evenly divisible by 2, 3, 5, 9 or 10 [with no remainder], then the answer is also yes because 834 is evenly divisible by both 2 and 3. It is not evenly divisible by 5, 9 and 10 but the 'or' in the question implies that it only need be divisible by one or more of the values, not necessarily all of them. If you really meant all of them, then the answer is no. In short, 834 is evenly divisible by 2 and 3, but not by 5, 9 or 10. It is obviously evenly divisible by 2 since 834 is an even number: 834 / 2 = 417. It is obviously evenly divisible by 3 since 834 / 3 is 278. It is obviously not evenly divisible by 5 since the least-significant digit (4) is neither 5 nor 0. It is obviously not evenly divisible by 9 because the digits do not recursively add up to 9. That is, 8 + 3 + 4 = 15 => 1 + 5 = 6. Ergo, 6 <> 9 therefore 834 is not evenly divisible by 9. It is obviously not evenly divisible by 10 since the least-significant digit (4) is not 0.
Because 410 ends in 0, it is divisble by 10. To determine if it's divisible by 6, it needs to be divisible by 2 and 3. it is divisible by 2, as it is even, but is not divisible by 3;
861 is divisible evenly by 3 but none of the others
No, it is not evenly divisible by 2359 nor by 10.
72,344 is evenly divisible by 2, but not by 3, 6, 9, 5, or 10.
It is evenly divisible by 3, 5 and 9 but not by 2, 6 or 10.
All multiples of 6 Numbers are evenly divisible by 6 if they are evenly divisible by both 2 AND 3. Even numbers are always evenly divisible by 2. Numbers are evenly divisible by 3 if the sum of all the individual digits is evenly divisible by 3. For example, the sum of the digits for the number 3627 is 18, which is evenly divisible by 3 but 3627 is an odd number so the number 3627 is not evenly divisible by 6