No. 23 is not divisible by anything except itself and one.
Yes, 5 × 23 = 115
Neither 23 or 5 divide evenly into 872.
No. 23 is prime, divisible only by one and itself.
To determine if 28751 is divisible by these numbers, we can check the divisibility rules. It is not divisible by 2 (as it is odd) or by 5 (since it does not end in 0 or 5). For 3, we sum the digits (2 + 8 + 7 + 5 + 1 = 23), which is not divisible by 3. Similarly, for 9, since 23 is not divisible by 9, 28751 is also not divisible by 9 or 10. Thus, 28751 is not divisible by 2, 3, 5, 9, or 10.
345 is divisible by: 1 3 5 15 23 69 115 and 345.
A number between 200 and 300 that is divisible by both 23 and 5 is 230. This is because 230 is the product of 23 and 10, and both 23 and 5 are factors of 230. Additionally, it falls within the specified range.
No. Is is divisible by 1, 5, 23, and itself. A prime number is divisible by only 1 and itself.
25 is divisible by 5 24 is divisible by 2,3,4,6,8,12 So the answer is 23
Only 1 and 23.
No. 3,569 is not evenly divisible by nine.
The number is 115.
23 is a prime number so it is not divisible by 3. It is only divisible by 1 and 23. Dividing 23 by three gives the result of 7.6r