No. 23 is prime, divisible only by one and itself.
To determine if 28751 is divisible by these numbers, we can check the divisibility rules. It is not divisible by 2 (as it is odd) or by 5 (since it does not end in 0 or 5). For 3, we sum the digits (2 + 8 + 7 + 5 + 1 = 23), which is not divisible by 3. Similarly, for 9, since 23 is not divisible by 9, 28751 is also not divisible by 9 or 10. Thus, 28751 is not divisible by 2, 3, 5, 9, or 10.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
It is evenly divisible by 2 and 10 but not by 3 and 9.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
It is divisible by 2, 5 and 10, but not 3 and 9.
23/3 = 7 and 2/3 = 7.666 (recurring) in decimal
The lowest number you could add to make it divisible by 10, 2, and 5 would be 7. 23 + 7 = 30 30/10 = 3 30/2 = 15 30/5 = 6 Also, technically, you could add (-3) to make 20. 23 + (-3) = 20 20/10 = 2 20/2 = 10 20/5 = 4 Basically, you could add any number to 23 that would get a multiple of 10, since 2 and 5 are both factors of 10 to begin with.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.
29,178 is divisible by 2, 3 and 9, not by 5 or 10.