No. It goes in 44 times with a remainder of 4.
268 is divisible by 1, 2, 4, 67, 134, 268.
268 is not divisible by 45 without remainder.
Yes, 268 is divisible by 2 and 4. To check if a number is divisible by 2, we just need to look at the ones place digit. If it is even, then the number is divisible by 2. In this case, the ones place digit of 268 is 8, which is even, so 268 is divisible by 2. To check if a number is divisible by 4, we need to look at the last two digits of the number. If the last two digits
Out of that list, only 4.
268 is divisible by 2, 4, 67, 134, and 268.
No.
268 is divisible by 1, 2, 4, 67, 134, 268.
1, 2, 4, 67, 134, 268.
1, 2, 4, 67, 134, 268
1, 2, 3, 4, 6, 12, 67, 134, 201, 268, 402, 804.
Any of its factors
The whole-number factors of 804 are 1, 2, 3, 4, 6, 12, 67, 134, 201, 268, 402, and 804.