It depends on what is meant by 2 and 14. The answer is: probably not.
the side lengths would be 7, 7, 2 ,2 so... 7*2=14<-- area or 14, 14,1, 1 so...14*1=14<-- area
Area: 6 + 4 + 2 + 2 = 14 ___ sq. units :)
Area = pi*r2 Area = pi(14 cm)2 = 616 cm2 =======
(pi) x (14)2 in2
Fixed area means that the measurement is given and does not change.
THEREFORE radius=14/2=7area=154cm.sq
A fixed area of a rectangle is an area that doesn't change. An area is a quantity that measures the space of a shape.Consider this example:A = length x width, which is the formula of a rectangleIf A is fixed, then it depends on what values length and width are. Then, length is indirectly proportional to width in order for A to remain fixed.
area of a triangle = (base x height)/2 = (4 units x 14 units)/2 =28 square units
Area = 1/2*(14+12)*8 = 104 square cm
Area = 1/2*16*14 = 112 square units
7..... b*h/2= area so 14=b*4/2... 14*2= 28... 28=4*b... b then has to equal 7.. just solve algebraicly
To maximize the area of a rectangle with a fixed perimeter, the rectangle should be a square. Given 14 inches of string, the perimeter ( P ) is 14, so each side of the square would be ( \frac{14}{4} = 3.5 ) inches. The area ( A ) of the square is then ( A = 3.5 \times 3.5 = 12.25 ) square inches. Thus, the largest rectangular area that can be enclosed is 12.25 square inches.