Q: Is 2x2 plus 5 factorable?

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yes it is

2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)

2x2 + 15x + 25 = (2x + 5)(x + 5)

2x2 equals 5

2x2 + 11x + 15 = (x + 3)(2x + 5).

-11

2x2+13x+15 = (2x+3)(x+5)

x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0

Not factorable

(x-1)(2x+5)

4x3+10x2+2x+5= (2x+5)(2x2+1)

2x^2+7x+5=(2x+5)(x+1)

x3 + 2x2 - 35x = x(x + 7)(x - 5)

2x2 + 9x + 10

Yes.(2x)2 = 2*2*x*xor2x2 = 2 * x * x

2x2 + 10 = 9x 2x2 - 9x + 10 = 0 (x - 2)(2x - 5) = 0

x = -1/2 or -5 2x2 + 11x + 5 = 0 ⇒ (2x + 1)(x + 5) = 0 ⇒ (2x + 1) = 0 → x = -1/2 or (x + 5) = 0 → x = -5

-2(x - 43)(x + 5)x = -5, 43

First you should combine equal terms. For example, 2x2 and -4x2 can be combined as -2x2. Then you can use the quadratic formula.Additonal Answer:-2x2+5x+3-4x2+22 = 0Collect like terms: -2x2+5x+25 = 0Divide al terms by -1: 2x2-5x-25 = 0Factorise: (2x+5)(x-5) = 0Solutions are: x = -5/2 or x = 5

-22

1x100/2x2/2x2/2x2/2x2/2x2/2x2/2x2/2+50 + -50 +50=100

2x2 + 10 - 9x = 0 or 2x2 - 9x + 10 = 0 So (x - 2)*(2x - 5) = 0

y=2x2+5. Plug in 0 for x, and you get y=2(0)^2 +5 =0+5=5. 5 is the minimum value for y.

2x2= 4

2x2 + 3x - 20 = (x + 4)(2x - 5).