First you should combine equal terms. For example, 2x2 and -4x2 can be combined as -2x2. Then you can use the quadratic formula.Additonal Answer:-2x2+5x+3-4x2+22 = 0Collect like terms: -2x2+5x+25 = 0Divide al terms by -1: 2x2-5x-25 = 0Factorise: (2x+5)(x-5) = 0Solutions are: x = -5/2 or x = 5
x3 + 2x2 + 5x + 4 = (x + 1)(x2 + x + 4)
If after finding all the factors of the product of the highest term's coefficient and the linear term, none of the can add or subtract to give the middle term then it is not factorable. x^2 +5x+6 is factorable. 1x6; 2x3 2+3=5 so it can be factored. x^2+7x+6 is factorable but x^2+8x+6 is NOT factorable because 1 and 6 as well as 2 and 3 can't add up to the middle term.
Divide all terms by 3:- 2x2+5x-3 = (2x-1)(x+3) when factored
2x2 + 5x = x*(2x + 5)
2x2 + 5x - 3 (2x - 1)(x + 3)
2x2 - 5x + 12 does not factor. 2x2 - 5x - 12 factors into (2x + 3)(x - 4) 2x2 + 5x - 12 factors into (2x - 3)(x + 4)
Yes.
2x2+5x+3 = (2x+3)(x+1) when factored
If you mean: x squared -5x +6 then it can be factored as (x-2)(x-3)
2x2 - 5x = 3 ∴ 2x2 - 5x - 3 = 0 ∴ 2x2 + x - 6x - 3 = 0 ∴ x(2x + 1) - 3(2x + 1) = 0 ∴ (x - 3)(2x + 1) = 0 ∴ x ∈ {-0.5, 3 }
2x2+5x-3 = 0 (2x-1)(x+3) = 0 x = 1/2 or x -3
2X2+5x-12 4+5x-12 -8+5x 5x-8
2x2+5x+3 = (2x+3)(x+1) when factored
the same question……
2x2-2 = -5x-1 2x2+5x-2+1 = 0 2x2+5x-1 = 0 Use the quadratic equation formula to find the values of x: x = 0.1861406616 or x = -2.686140662
You would first factor out anything that is common between the 3 parts. 2x2 is the greatest common factor. To pull out the 2x2, you divide each term by 2x2 like so:12x4/2x2=6x210x3/2x2=5x-12x2/2x2=-6We now know that 12x4+10x3-12x2= 2x2(6x2+5x-6)The next step involves using the "slip and slide" method for the trinomial inside the parentheses:6x2+5x-6x2+5x-36(x+9)(x-4)(x+9/6)(x-4/6)(x+3/2)(x-2/3)(2x+3)(3x-2)Remembering that the result for the slip and slide method only accounts for 6x2+5x-6 we must multiply (2x+3)(3x-2) by 2x2.Your final answer is 2x2(2x+3)(3x-2).