no
Using exponets is easy. Like 23. This is 2 cubed. 23 equals 2.2.2. It is not 2x3. 2x2x2=8. Get it?
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2x3 + 16 = 2(x3 + 8) = 2(x3 + 23) = 2(x + 2)(x2 - 2x + 22) = 2(x + 2)(x2 - 2x + 4)
It is an expression which can be written in the form of: 2x3+x+3
2X3 2 + 2 + 2 = 6 3 + 3 = 6 ^ thats how ^
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
(2x3)+(3x5)-(3x2)= 2x3=6 3x5=15 3x2=6 So..... 6x25-6= 6x25=150 150+6=156
21
False
f'(x) = 1/(2x3 + 5) rewrite f'(x) = (2X3 + 5) -1 use the chain rule d/dx (2x3 + 5) - 1 -1 * (2x3 + 5)-2 * 6x2 - 6x2(2x3 + 5) -2 ==================I would leave like this rather than rewriting this
Since 6 equals 2 times 3, this expression can be written as:(2x3)x(2x3)x3x3x2x23x3x3x3x2x2x2x2Notice that there are four 3's and four 2's being multiplied. This can be written in exponential notation as:3424, or 34x24In other words, 3 four times multiplied by 2 four times.
What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).