your equation is this...
2x3 + 11x = 6x
2x3 + 5x = 0
x(2x2 + 5) = 0
x = 0 and (5/2)i and -(5/2)i
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5x + 32 = 11x - 105x - 11x = -10 - 32-6x = -42x = 7
2x^3-3x^2-11x+7x+32x^2-9x+16 R -41x+3 l 2x^3-3x^2-11x+7-(2x^3+6x^2)-9x^2-11x+7-(-9x^2-27x)16x+7-(16x+48)-412x^2-9x+16-[41/(x+3)]
4x + 6 = 6x - 12-4x -4x6 = 2x - 12+12 +1218 = 2xx=9
3x - 8 = 7 so x = 5
5x + 3 = 6x + 1 Subtract 5x from both sides: 3 = x + 1 Subtract 1 from both sides: 2 = x