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What is the answer to the rational expression 2x plus 3 over 10x squared plus 21x plus 9?
(2x+3)/(10x2+21x+9)Factor the quadratic expression in the denominator:(2x+3)/(5x+3)(2x+3)which becomes:1/(5x+3) or (5x+3)-1
What is the rate of change for the linear function y equals 2x plus 3?
The rate of change for the linear (not liner) function, y = 2x +/- 3 is 2.
What is 11 over 2x minus 3 over x?
5/2x
What is the rate of change for the liner function y -2x-3?
If you mean: y = -2x-3 then the slope is -2 and the y intercept is -3
Y equals -3over2x plus 1?
y = -3/2x + 1y = (-3 + 2x)/2x ory = (2x - 3)/2xWe have to deal with a rational function here f(x) = p(x)/q(x), where 2x ≠ 0, or x ≠ 0. So that the domain of f is the st of all real numbers except 0, and the y-axis (the line x = 0) is a vertical asymptote of the graph of f.Since the degree of the numerator and denominator is the same (degree 1), then the line y = 2/2 (an/bn) or y = 1, is the horizontal asymptote of the graph of f.y = (2x - 3)/2xx = 0, gives us the y-intercept, but in our case x cannot be zero, so we don't have y-intercept here.y = 0, gives us the x-intercept which is 3/2.y = (2x - 3)/2x0 = (2x - 3)/2x0 = 2x - 30 + 3 = 2x - 3 + 33 = 2x3/2 = 2x/23/2 = xSince f(-x) ≠ f(x) or -f(x), then the the graph of f has nether y-axis nor origin symmetry.y = -3/2x + 1 orf(x) = -3/2x + 1f(-x) = -3/2(-x) + 1f(-x) = 3/2x + 1-f(x) = -(-3/2x + 1)-f(x) = 3/2x - 1We can graph the function by plotting points between and beyond the x-intercept (x = 3/2) and vertical asymptote (x = 0).So we can valuate the function at -2, -1, 1, and 2.Graph the function:
What is the answer to the rational expression 2x plus 3 over 10x squared plus 21x plus 9?
(2x+3)/(10x2+21x+9)Factor the quadratic expression in the denominator:(2x+3)/(5x+3)(2x+3)which becomes:1/(5x+3) or (5x+3)-1
What is equal to the rational expression when x 5 or negative 3 x2 plus x-6 over x2-2x-15?
When x = -3
How do you rewrite as a function of x using function notation for 2x plus 3y equals 4?
If 2x + 3y = 4, y= (4 - 2x)/3. In function notation, f(x) = (4 - 2x)/3.
How do you factor 6x2-7x-35?
Since the discriminant, b2-4ac is not a perfect square, there are no rational roots and so these are no rational factors.
If a function rule is 2x - 3 what is the output for 3?
Where Y = 2x-3, the output for x = 3 is Y = 3. 2x - 3 = 2(3)-3 = 6-3 = 3
What is the rate of change for the linear function y equals 2x plus 3?
The rate of change for the linear (not liner) function, y = 2x +/- 3 is 2.
What is 11 over 2x minus 3 over x?
5/2x
What is the discontinuity and zero of the function fx the quantity of 2 x squared plus 5 x minus 12 all over x plus 4?
f(x) = (2x^2 + 5x - 12)/(x + 4) as given, is not defined when the denominator is 0 ie when x + 4 = 0 or x = -4. However, 2x^2 + 5x - 12 = (x + 4)*(2x - 3) so that the function can be simplified to (x + 4)*(2x - 3)/(x + 4) = 2x - 3 This has a zero when 2x - 3 = 0 ie 2x = 3 or x = 1.5
What is the rate of change for the liner function y -2x-3?
If you mean: y = -2x-3 then the slope is -2 and the y intercept is -3
Is 0.3 with a bar over it a rational number?
Yes. 0.3 with a bar over it is 1/3, which is a rational number.
Is 100 over 3 rational or irrational?
100/3 is a rational number
Y equals -3over2x plus 1?
y = -3/2x + 1y = (-3 + 2x)/2x ory = (2x - 3)/2xWe have to deal with a rational function here f(x) = p(x)/q(x), where 2x ≠ 0, or x ≠ 0. So that the domain of f is the st of all real numbers except 0, and the y-axis (the line x = 0) is a vertical asymptote of the graph of f.Since the degree of the numerator and denominator is the same (degree 1), then the line y = 2/2 (an/bn) or y = 1, is the horizontal asymptote of the graph of f.y = (2x - 3)/2xx = 0, gives us the y-intercept, but in our case x cannot be zero, so we don't have y-intercept here.y = 0, gives us the x-intercept which is 3/2.y = (2x - 3)/2x0 = (2x - 3)/2x0 = 2x - 30 + 3 = 2x - 3 + 33 = 2x3/2 = 2x/23/2 = xSince f(-x) ≠ f(x) or -f(x), then the the graph of f has nether y-axis nor origin symmetry.y = -3/2x + 1 orf(x) = -3/2x + 1f(-x) = -3/2(-x) + 1f(-x) = 3/2x + 1-f(x) = -(-3/2x + 1)-f(x) = 3/2x - 1We can graph the function by plotting points between and beyond the x-intercept (x = 3/2) and vertical asymptote (x = 0).So we can valuate the function at -2, -1, 1, and 2.Graph the function:
