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What is the determinant of a 2x3 matrix?
The determinant function is only defined for an nxn (i.e. square) matrix. So by definition of the determinant it would not exist for a 2x3 matrix.
How can you find 2x3?
2X3 2 + 2 + 2 = 6 3 + 3 = 6 ^ thats how ^
What is the f dashed x or deriative of 1 over 2xcubed plus 5?
f'(x) = 1/(2x3 + 5) rewrite f'(x) = (2X3 + 5) -1 use the chain rule d/dx (2x3 + 5) - 1 -1 * (2x3 + 5)-2 * 6x2 - 6x2(2x3 + 5) -2 ==================I would leave like this rather than rewriting this
How do you solve sums based on commutative property of multiplication?
The commutative property of multiplication states that changing the order of numbers does not change the result or it's value. For example: If 3+2=5 Then 2+3=5 In multiplication: If 3x2=6 Then 2x3=6 There for 3x2=2x3
Factor 4x5 plus 6x3 plus 6x2 plus 9?
Rearrange: 4x5 + 6x2 + 6x3 + 9 Group: 2x2 (2x3 + 3) + 3 (2x3 + 3) Simplify to get your answer: (2x2 + 3) (2x3 + 3)
What is the determinant of a 2x3 matrix?
The determinant function is only defined for an nxn (i.e. square) matrix. So by definition of the determinant it would not exist for a 2x3 matrix.
How do you find out if the function is a even odd or neither I know your supposed to use f-x -fx but I am not so sure how to do it the problem is 2x to the third power minus x squared?
An even function is symmetric around the vertical axis. An odd function - such as the sine function - has a sort of symmetry too - around the point of origin. If you graph this specific function (for example, on the Wolfram Alpha website), you can see that the function has none of these symmetries. To prove that the function is NOT even, nor odd, just find a number for which f(x) is neither f(-x) nor -f(-x). Actually proving that a function IS even or odd (assuming it actually is) is more complicated, of course - you have to prove that it has the "even" or the "odd" property for EVERY value of x. Let f(x) = 2x3 - x2. Notice that f is defined for any x, since it is a polynomial function. If f(-x) = f(x), then f is even. If f(-x) = -f(x), then f is odd. f(-x) = 2(-x)3 - (-x)2 = -2x3 - x2 Since f(-x) ≠ f(x) = 2x3 - x2, f is not even. Since f(-x) ≠ - f(x) = -(2x3 - x2) = -2x3 + x2, f is not odd. Therefore f is neither even nor odd.
How can you find 2x3?
2X3 2 + 2 + 2 = 6 3 + 3 = 6 ^ thats how ^
2x3 plus 3x5- 3x2 equals?
(2x3)+(3x5)-(3x2)= 2x3=6 3x5=15 3x2=6 So..... 6x25-6= 6x25=150 150+6=156
What is 2x3 plus 11x equals 6x?
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
What is the f dashed x or deriative of 1 over 2xcubed plus 5?
f'(x) = 1/(2x3 + 5) rewrite f'(x) = (2X3 + 5) -1 use the chain rule d/dx (2x3 + 5) - 1 -1 * (2x3 + 5)-2 * 6x2 - 6x2(2x3 + 5) -2 ==================I would leave like this rather than rewriting this
1x3=2x3?
False
What is 27-2x3?
21
Is 2x3 can be written as 23?
no
How do you solve sums based on commutative property of multiplication?
The commutative property of multiplication states that changing the order of numbers does not change the result or it's value. For example: If 3+2=5 Then 2+3=5 In multiplication: If 3x2=6 Then 2x3=6 There for 3x2=2x3
What is the factor 2x3-8x2 plus 6x?
What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).
Factor 4x5 plus 6x3 plus 6x2 plus 9?
Rearrange: 4x5 + 6x2 + 6x3 + 9 Group: 2x2 (2x3 + 3) + 3 (2x3 + 3) Simplify to get your answer: (2x2 + 3) (2x3 + 3)
