Yes but it will have a remainder
1, 3, 103, 309. it is also divisible by 6!
no
1, 3, 9, 103, 309, 927.
1, 3, 9, 103, 309, 927
Both 927 / 3 = 309 927 / 9 = 103
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
YES. 285 is divisible by 5. A number is divisible by 5 if it ends with 0 or 5
Yes, 1255 is divisible by 5, and any number that ends in 5 is divisible by 5.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
No, because 1 is not evenly divisible by 5. However, all numbers divisible by 5 are divisible by 1.
1, 2, 3, 4, 6, 12, 103, 206, 309, 412, 618, 1236.