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1, 3, 103, 309. it is also divisible by 6!
1, 3, 9, 103, 309, 927.
Try dividing the number by 19. If the answer is a whole number (with no remainder), then the number is divisible by 19.
The first 3 digit number divisible by 19 is 114 (= 19 x 6) The last 3 digit number divisible by 19 is 988 (= 19 x 52) That means that there are 52 - 6 + 1 = 47 three digit numbers that are divisible by 19.
They are both divisible by 1 and 19.