Top Answer

Yes, by 2, 3, 6, and 9. No by 4, 5 and 10.

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1The prime factors are 342 are 2, 3, 3, and 19. Thus the numbers 342 is divisible by are 1, 2, 3, 6, 9, 18, 19, 36, 38, 57, and 342.

Divide it by 3. In this case, 342 IS divisible by 3, because we get 114 instead of a fraction.And the quicker way is: Add the digits: 3+4+2 = 9If the sum of digits is divisible by 3 then the number is divisible by 3. 9 is divisible by 3 so is 342.

If the digits add up to a multiple of three for example: 52039 5+2+0+3+9=19 19 is not divisible by 3 so 52039 is not divisible by 3 --------- 342 3+4+2=9 9 is divisible by 3 so 342 is divisible by 3

by 2 is 171 by 3 is 114 by 4 is not evenly divisible nor by 5, by 6 it is evely divisible 57 times, by 9 its 38 not evenly by 10.

yes, you know that because if you add the digits together and that number is divisible by 9, then that large number is divisible by 9. 3+4+2 is 9, which is divisible by 9. conclusion 342 is divisible by 9.

It is divisible by 2 and 3. It isn't divisible by 5 and 10.

1, 2, 3, 6, 9, 18, 19, 38, 57, 114, 171, 342.

The digits of a multiple of three sum to a multiple of three. for 342, 3+4+2 = 9 Since 9 is a multiple of three, 342 is as well. It is the product of 114 and 3

If a number is even, it's divisible by two. If the digits of a number add up to a multiple of 3, it's a multiple of 3. For example, 342 is divisible by 3 because 3 + 4 + 2 = 9 and 9 is divisible by 3.

It is evenly divisible by 2 and 10 but not by 3 and 9.

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.

9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.

20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.

Yes, The quotient is 114.

It is divisible by 2, 5 and 10, but not 3 and 9.

29,178 is divisible by 2, 3 and 9, not by 5 or 10.

It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10

It is evenly divisible by 2 and by 3.

Because 410 ends in 0, it is divisble by 10. To determine if it's divisible by 6, it needs to be divisible by 2 and 3. it is divisible by 2, as it is even, but is not divisible by 3;

It is divisible by 2, 5 and 10 but not the rest.

No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.

Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10

475 is evenly divisible by 5, but not by 2, 3, 4, or 10.

Yes it is divisible by 2

It is only divisible by 3, and not 2, 4, 5, 6, or 10.

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