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Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.

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Q: Is 432 divisible by 2 3 5 9 or 10?

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432/3 = 144 432/4 = 108 432 is divisible by both 3 and 4.

Numbers divisible by 9 have the sum of their digits equal to 9 or a multiple of 9. A number divisible by 2 is an even number. If a 3 digit number is 42n then n can only be 3 if the number is divisible by 9 and 423 is not within the specified range. If a 3 digit number is 43n then n must be 2 for it to be divisible by 9.. The number is thus 432 and this is even and so divisible by 2. If the 3 digit number is 44n then n must be 1 and 441 is odd and not divisible by 2. The only valid solution is 432.

It is evenly divisible by 2 and 10 but not by 3 and 9.

20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.

It is divisible by 2, 5 and 10, but not 3 and 9.

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No, but 432 is divisible by 2 and 3.

None of them. 432 is divisible by 2, 3, 4, 6, 8 and 9.

432 is divisible by 2 and 3.

432 is divisible evenly by both 2 and 3

To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.

No.

432/3 = 144 432/4 = 108 432 is divisible by both 3 and 4.

If you want to know if a number is prime or composite, begin by looking at it. The last digit of 432 is even; that means that 432 is divisible by two, so it can't be prime. Look again. Add up the digits of 432. 4 + 3 + 2 = 9. 9 is divisible by 3, so 432 is divisible by 3. Not prime. In fact 432 is about as composite as you can get. It is 2 X 2 X 2 X 2 X 3 X 3 X 3.

432 ÷ 3 = 144

432 is divisible by 3 and 4 because the quotients are whole numbers. 432/3 = 144 432/4 = 108

yes 432/2 = 216 432/3 = 144 432/4 = 108 432/6 = 72 432/8 = 54 432/9 = 48

Yes 3 x 144 = 432.